0
y = -5tan(x) can also be written y/(-5) = tan(x). In other words, the -5 just changes the y values and the orientation of the graph (it flips tan(x) over the y axis and stretches the graph up and down).
So -5tan(x), like tan(x), has a period of pi. This is because tan is the y value divided by the x value at any given point on the unit circle. At 0 degrees, x is at one and y is at zero, so tan0o = 0. As we travel counterclockwise around the unit circle, tan is next equal to zero when x is equal to zero. This occurs halfway around the circle at 180o, or (in radians) pi.
Still curious? Ask our experts.
Chat with our AI personalities
Judy
Jordan
RafaAdd your answer:
Earn +20 pts
What is tan x degree 90?
To solve for tan x degree 90 you do a few things. First, if x equals 90, then this equals 1.5597 radian or 89.36 degrees. This is the easiest way to solve tan x degree 90.
What is the derivative of y equals sec x?
sec(x)tan(x)
How do you find the period of tangent function?
You find the smallest positive value y such that tan(x + y) = tan(x) for all x.
What is cot of pi - pi over 4 given that tan of pi over 4 equals 1?
First: note 3 things about cot and tan, and note the given statement:cot = 1/tantan is cyclic with a period of π, that is tan(nπ + x) = tan(x)tan is an odd function, that is tan(-x) = -tan(x)tan(π/4) = 1Now apply them to the problem:cot(π - π/4) = 1/tan(π - π/4)= 1/tan(-π/4)= 1/-tan(π/4)= 1/-1 = -1Thus:cot(π - π/4) = -1.
What is Sin squared x - Cos squared x divided by 1 - Tan squared x equals cos squared x?
22
