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What is the range y equals - sin x?
Assuming a large enough domain, the range is -1 to 1.
Verify that sin minus cos plus 1 divided by sin plus cos subtract 1 equals sin plus 1 divided by cos?
[sin - cos + 1]/[sin + cos - 1] = [sin + 1]/cosiff [sin - cos + 1]*cos = [sin + 1]*[sin + cos - 1]iff sin*cos - cos^2 + cos = sin^2 + sin*cos - sin + sin + cos - 1iff -cos^2 = sin^2 - 11 = sin^2 + cos^2, which is true,
What does cosx divided by 1-sinx equal?
cos x / (1-sin x) = cos x (1 + sin x) / (1 - sin x) (1 + sin x) = cos x (1 + sin x) / (1 - sin2x) = cos x (1 + sin x) / cos2 x = (1 + sin x) / cos x = sec x + tan xcos x / (1-sin x) = cos x (1 + sin x) / (1 - sin x) (1 + sin x) = cos x (1 + sin x) / (1 - sin2x) = cos x (1 + sin x) / cos2 x = (1 + sin x) / cos x = sec x + tan xcos x / (1-sin x) = cos x (1 + sin x) / (1 - sin x) (1 + sin x) = cos x (1 + sin x) / (1 - sin2x) = cos x (1 + sin x) / cos2 x = (1 + sin x) / cos x = sec x + tan xcos x / (1-sin x) = cos x (1 + sin x) / (1 - sin x) (1 + sin x) = cos x (1 + sin x) / (1 - sin2x) = cos x (1 + sin x) / cos2 x = (1 + sin x) / cos x = sec x + tan x
What is the arc sine of 1.5 degrees?
if x if ArcSine 1.5 degrees means the sin(x)=1.5 but the range of the sin(theta) for all angles theta is between o and 1 inclusive. So there is no real answer.
How do you solve csc x sin x equals cos x cot x plus?
Suppose csc(x)*sin(x) = cos(x)*cot(x) + y then, ince csc(x) = 1/sin(x), and cot(x) = cos(x)/sin(x), 1 = cos(x)*cos(x)/sin(x) + y so y = 1 - cos2(x)/sin(x) = 1 - [1 - sin2(x)]/sin(x) = [sin2(x) + sin(x) - 1]/sin(x)
What is the range of y equals -sin x?
The range of -sin x depends on the domain of x. If the domain of x is unrestricted then the range of y is [-1, 1].
Find the domain and range of sin x - cos x?
sin(x)-cos(x) = (1)sin(x)+(-1)cos(x) so the range is sqrt((1)^2+(-1)^2)=1 and the domain is R <><><><><> The domain of sin x - cos x is [-infinity, +infinity]. The range of sin x - cos x is [-1.414, +1.414].
What is the range of y equals -3 sin x?
sin x can have any value between -1 and 1; therefore, 3 sin x has three times this range (from -3 to 3).
What is the range y equals - sin x?
Assuming a large enough domain, the range is -1 to 1.
What is the range of the graph of y equals sin x?
the range is greater then -1 but less than 1 -1<r<1
What is the domain and range for sin?
The domain of the sine function, ( \sin(x) ), is all real numbers, represented as ( (-\infty, \infty) ). The range of the sine function is limited to values between -1 and 1, inclusive, which is expressed as ( [-1, 1] ).
Sin x -1?
Sin x -1 is a function whose domain and range includes complex values. All angles are in radians.
Can cosine x equal -3?
No.-1
What is sin-1?
The term "sin-1" typically refers to the inverse sine function, also known as arcsine, denoted as ( \sin^{-1}(x) ) or ( \arcsin(x) ). This function takes a value ( x ) in the range of -1 to 1 and returns an angle ( \theta ) in radians (or degrees) such that ( \sin(\theta) = x ). The output of the arcsine function is restricted to the range ([- \frac{\pi}{2}, \frac{\pi}{2}]) to ensure it is a well-defined function.
Solution for tan x is equal to cos x?
if tan x = cos x then sin x / cos x = cos x => sin x = cos x cos x => sin x = cos2 x => sin x = 1 - sin2x => sin2x + sin x - 1 = 0 Using the quadratic formula => 1. sin x = 0.61803398874989484820458683436564 => x = sin-1 (0.61803398874989484820458683436564) or => 2. sin x = -1.6180339887498948482045868343656 => x = sin-1 (-1.6180339887498948482045868343656)
Is it a function if the range is repeated?
Yes. As long as there is only 1 value for each argument, it is a function. For example, the range of the sine function (y = sin x), for real values of x, consists of all the real numbers from -1 to 1 inclusive, and this range repeats infinitely many times. But for each value of x, there is only 1 value of sin x.
Domains and ranges of sinx?
If y = sin x:x can take on any value, so the domain is the set of real numbers.y can take on values between -1 and 1 (including the extremes); so the range is -1
