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What is the slope of line passing through the points (35) and (-26)?
If you mean points of (-2, -1) and (3, 5) then the slope is 6/5
What is 35 is to 1 glide slope?
That is a very small glide slope. The glide slope is the amount an aircraft (or bird or whatever) sinks as it glides parallel to the ground. 35:1 means it will glide 35 meters (measured along the ground) and descend 1 meter (vertically) in still air (no updraft).
What is the distance from 53 and 35 on a number line?
The distance between 53 and 35 on a number line is the absolute value of 35-53, or 18.
What is the equation that represents the line perpendicular to 2y equals 7x if the y-intercept is b equals 5?
If the original line has the equation 2y = 7x then this can be written as y = 3.5x and the slope of this line is thus 3.5. Two straight lines are perpendicular if the product of their gradients is -1. Let m be the slope of the perpendicular line then, 3.5m = -1 : m = -1/3.5 = -2/7 The equation of the perpendicular line is thus, y = -2/7 * x + b where b is the intercept. As b = 5 then the equation becomes y = -2/7*x + 5 We can multiply by 7 to eliminate the fraction, 7y = -2x + 35 and re-order the terms to become 7y = 35 - 2x
How do you determine if three points are collinear?
Since any 2 points determine 1 line, take 2 of the points and find the equation of the line drawn thru these 2 points. Substitute the x and y of the either point into the equation and find the y-intercept (b) Then, substitute the x and y of the 3rd point into the equation and see if the both sides of the equation are =. (y2-y1) ÷ (x2 - x1) = slope y = slope * x + b Point # 1 = (6, 5) Point # 2 = (10, 25) Point # 3 = (12, 30) Point # 4 = (12, 35) (y2 - y1) ÷ (x2 - x1) = slope (25 - 5) ÷ (10 - 6) = slope (20) ÷ (4) = slope Slope = 5 y = m * x + b y = 5 * x + b Substitute the x and y of the point (6, 5) into the equation and find the y-intercept (b) y = 5 * x + b 5 = 5 * 6 + b 5 = 30 + b b = -25 y = 5 * x - 25 . Check your points Point # 1 = (6, 5) 5 = 5 * 6 - 25 5 = 30 - 25 OK . Point # 2 = (10, 25) 25 = 5 * 10 - 25 25 = 5 * 10 - 25 OK . Then, substitute the x and y of the 3rd point into the equation and see if the both sides of the equation are Point # 3 = (12, 30) . y = 5 * x - 25 30 = 5 * 12 - 25 30 = 60 - 25 = 35 Point # 3 = (12, 30) is not on the line . . Point # 4 = (12, 35) 35 = 5 * 12 - 25 35 = 60 - 25 =35 Point # 4 = (12, 35) is on the line
