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There is no visible symbol between 2x and 5, or 5 and 0.
(x2+3x-4) (x-4)
X2 - X - 6 = 0what two factors of - 6 add up to - 1 ?(X + 2)(X - 3)============(- 2, 0 ) and (3, 0 )------------------------------solution set of points
An equation with the solution set 1 and 3 can be written in factored form as (x-1)(x-3) = 0. When expanded, this equation becomes x^2 - 4x + 3 = 0. Therefore, the equation x^2 - 4x + 3 = 0 has the solution set 1 and 3.
x2+2x-15
x2 + 2x + 2 = 0 Use the quadratic formula: x = (-2 +- sqrt(4 - 8))/2 x = (-2 +- 2i)/2 = -1 +- i
(-4,6)
Without the inclusion of an equality sign the given expression can't be considered to be an equation
Using the quadratic formula, you get the complex answers of 1 + 2i and 1 - 2i
If you mean to say (x^2)-2x+4=0 then there is no solution for x because the equation never makes it to 0 If you mean to say 2x-2x+4=0 then there is no solution for x because it is a horizontal line at Y=4
x2+10x+1 = -12+2x x2+10x-2x+1+12 = 0 x2+8x+13 = 0 Solving by using the quadratic equation formula: x = - 4 - or + the square root of 3
have to put it was 2x and not x2--back to the problem--2x-x-4=0x=4* * * * *True, but the question, in all likelihood WAS x2 - x - 4 = 0and the solutions to that equation are -1.561553 and 2.561553
There are no such real numbers.Let the numbers be x and (2-x). The equation representing the question is:x(2-x) = 24 2x-x2 = 24 2x = x2+24 0 = x2-2x+24 x2-2x+24=0.In solving this equation, a=1, b=-2 and c=24. The discriminant is b2-4ac = (-2)2-4(1)(24) = 4-96 = -92.Since the discriminant is negative, the equation has no solution.
A solution point, in R2, is an ordered pair that satisfies the function.e.g. given the function, f(x) = x2, a solution point is (0,0), or (2,4), etc.The set of all solution points of an equation is equivalent to the graph of an equation.
x2 + 2x = 3 x2 + 2x - 3 = 0 x2 + 2x - 3 = y Graph the equation in a calculator and find its zeros, which are x = -3 and x = 1. Check: x2 + 2x = 3 (-3)2 + 2(-3) =? 3 9 - 6 =? 3 3 = 3 True (1)2 + 2(1) =? 3 1 + 2 =? 3 3 = 3 True
(x2+3x-4) (x-4)
x2 - 2x - 15 = 0
x2 - 10x - 6 = 2x + 1 Subtracting 2x + 1 from both sides gives: x2 - 12x - 7 = 0