sum of n natural number is n(n+1)/2 first 50 number sum is 50(50+1)/2 = 1275
Using the formula for the sum of an arithmetic sequence;Sum = 1/2*n [n is the total number of terms] *(2a [a is the value of the first term] + (n-1) * d)[d is the common difference between each term]So the formula looks like this: Sum = 1/2*n (2a+(n-1)*d)n = 50 because there's 50 odd numbers in a hundred and 50 even numbers (50+50=100)a = 1d = 2So inputting the values gives:Sum= 1/2*50 (2*1+(50-1)* 2)Sum= 25*(2+49*2)Sum= 25*(2+98)Sum= 25*(100)Sum= 2500Answer= 2,500
i got the same question for homework in functions. tn=a+(n-1)d -50=-1+(n-1)-1 -50=-1-1n+1 -50=-1n therefore n=50 plug that into your sum equation...for convenience i used Sn=50/2 (-1-50) Sn=25 (-51) Sn= -1275 hope this helps!
(50 + 15) = 65 (50 x 15) = 750 1/50 + 1/15 = 13/150
The sum of 9 odd numbers must be odd and so cannot be an number.
flow chart that computes the sum from 1 to 50
The sum of the composite numbers between 1 and 50 is 936.
51
sum of n natural number is n(n+1)/2 first 50 number sum is 50(50+1)/2 = 1275
Why, that's just 6 times the sum of the numbers from 1 to 50 !The sum of the numbers from 1 to 50 is:1 + 50 = 512 + 49 = 513 + 48 = 514 + 47 = 515 + 46 = 51...etc. There are 25 pairs, and each pair sums to 51. So the sum of 1 ... 50 is (25 x 51) = 1,275.The sum of the first 50 multiples of 6 is (1,275 x 6) = 7,650.
50
It doesn't make sense to ask for the sum of just one thing.This is like asking what the sum of 1 is. Or what the sum of a tv is. Well, the sum of 1 is in fact 1. So technically, the answer to your question would be:a 50 side shape
Using the formula for the sum of an arithmetic sequence;Sum = 1/2*n [n is the total number of terms] *(2a [a is the value of the first term] + (n-1) * d)[d is the common difference between each term]So the formula looks like this: Sum = 1/2*n (2a+(n-1)*d)n = 50 because there's 50 odd numbers in a hundred and 50 even numbers (50+50=100)a = 1d = 2So inputting the values gives:Sum= 1/2*50 (2*1+(50-1)* 2)Sum= 25*(2+49*2)Sum= 25*(2+98)Sum= 25*(100)Sum= 2500Answer= 2,500
51
The sum of the numbers 1 through 50 can be found using the formula for the sum of an arithmetic series: [(n/2) * (first term + last term)], where n is the number of terms. In this case, n = 50 and the first term is 1 and the last term is 50. Plugging those values into the formula, the sum is 1275.
i got the same question for homework in functions. tn=a+(n-1)d -50=-1+(n-1)-1 -50=-1-1n+1 -50=-1n therefore n=50 plug that into your sum equation...for convenience i used Sn=50/2 (-1-50) Sn=25 (-51) Sn= -1275 hope this helps!
The nine odd numbers whose sum is 50 are 1, 3, 5, 7, 9, 11, 13, 15, and 1.