90
The first 3 multiples of 6 are: 6, 12, and 18.
Why, that's just 6 times the sum of the numbers from 1 to 50 !The sum of the numbers from 1 to 50 is:1 + 50 = 512 + 49 = 513 + 48 = 514 + 47 = 515 + 46 = 51...etc. There are 25 pairs, and each pair sums to 51. So the sum of 1 ... 50 is (25 x 51) = 1,275.The sum of the first 50 multiples of 6 is (1,275 x 6) = 7,650.
6,12,18
30, 60 and 90.
The sum of three consecutive multiples of 6 is 666, the multiples are 216, 222 and 228.
the first three multiples are 6, 12, 18.
90
5 + 10+15+20=50 ans
The first 3 multiples of 6 are: 6, 12, and 18.
Let the second of the three consecutive multiples of 6 be 6n Then the first is 6n - 6 and the last is 6n + 6; and: (6n - 6) + 6n + (6n + 6) = 666 → 18n = 666 → n = 37 → the consecutive multiples of 6 which sum to 666 are 216, 222, 228
1 x 6 = 62 x 6 = 12The sum of 12 + 6 = 18
6+12+18+24+30=90
6 + 12 + 18 + 24 + 30 + 36 = 126
First three common multiples of 2 and 6 are 6, 12 and 18.
The first three multiples of 2 are 2, 4, 6. For them to be common, they need to be compared to another set of multiples.
That's going to depend on where you start and in which direction you go. If you begin at zero and move in the direction of increasing numbers, then the first three multiples of 3 are 3, 6, and 9, the first three multiples of 2 are 2, 4, and 6, and the first three COMMON multiples of 2 AND 3 that you'll encounter are 6, 12 and 18.