1 x 6 = 6
2 x 6 = 12
The sum of 12 + 6 = 18
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To find the sum of the first 4 multiples of 6, you can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum, n is the number of terms, a1 is the first term, and an is the last term. In this case, the first 4 multiples of 6 are 6, 12, 18, and 24. Plugging these values into the formula, you get Sn = 4/2 * (6 + 24) = 2 * 30 = 60. Therefore, the sum of the first 4 multiples of 6 is 60.
5 + 10+15+20=50 ans
6+12+18+24+30=90
3+6+9...+45taking 3 common3(1+2+...+15) = 360
2,4,6,8,10,12
To find the sum of the first 4 multiples of 6, you can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum, n is the number of terms, a1 is the first term, and an is the last term. In this case, the first 4 multiples of 6 are 6, 12, 18, and 24. Plugging these values into the formula, you get Sn = 4/2 * (6 + 24) = 2 * 30 = 60. Therefore, the sum of the first 4 multiples of 6 is 60.
90
5 + 10+15+20=50 ans
It is: 6+12+18 = 36
The sum of three consecutive multiples of 6 is 666, the multiples are 216, 222 and 228.
6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90.
6+12+18+24+30=90
3+6+9...+45taking 3 common3(1+2+...+15) = 360
First three common multiples of 2 and 6 are 6, 12 and 18.
0, 2, 4, 6, 8.0,2,4,6,8 are the first five multiples of 2
2
6 and 12.