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Christian Sawayn
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∙ 12y agoA binomial expression that can be factored out as x(x - 6)
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How do you solve x2 6x 27?
please help on this x2+6x+27=
X2 plus 6x plus 9 equals 81?
x2 + 6x + 9 = 81 x2 + 6x = 72 x2 + 6x - 72 = 0 (x+12)(x-6) = 0 x= -12, 6 (two solutions)
Factoris x2 6x 5?
x2 + 6x + 5 = (x + 1)(x + 5)
What are the factors of the polynomial below x2 6x-27?
x2 + 6x - 27 = (x + 9)(x - 3)
What are the roots of x2 plus 6x plus 12 equals 0?
x2 + 6x + 12 = 0 x2 + 6x + 9 = -3 (x + 3)2 = -3 x + 3 = ± √-3 x = -3 ± i√3
How do you factor x2 6x-2?
x2 + 6x - 2 can not be factored
How do you solve x2 6x 27?
please help on this x2+6x+27=
How do you Factorise this x2 plus 6x?
x2 + 6x = x*(x + 6)
If x is a positive integer solve x2 6x 16?
Um.......is it x2+6x or x2-6x. I think your missing some things here champ
X2 - 6x - 16?
x2 - 6x - 16 = (x - 8)(x + 2)
-x2 plus 6x plus 16?
-x2 + 6x + 16 = -(x2 - 6x - 16) = -(x - 8)(x + 2) = -(8 - x)(x + 2)
X2 plus 6x plus 9 equals 81?
x2 + 6x + 9 = 81 x2 + 6x = 72 x2 + 6x - 72 = 0 (x+12)(x-6) = 0 x= -12, 6 (two solutions)
Factoris x2 6x 5?
x2 + 6x + 5 = (x + 1)(x + 5)
What is the factorization of x3 -7x2 plus 6x?
x3 - 7x2 + 6x = x(x2 - 7x + 6) = x(x2 - x - 6x + 6) = x[x(x - 1) - 6(x - 1)] = x2(x - 1) - 6x(x - 1) = (x2 - 6x)(x - 1)
What is x2 -6x 8 factored?
x2-6x+8 = (x-2)(x-4) when factored
X3 plus x2 minus 6x plus 4?
x3 + x2 - 6x + 4 = (x - 1)(x2 + 2x - 4)
How do you complete the square x2 - 6x equals 16?
x2 - 6x = 16 ∴ x2 - 6x + 9 = 25 ∴ (x - 3)2 = 25 ∴ x - 3 = 25 ∴ x = 28
