The area would become four times larger. The area increase is always the perimeter increase, squared. For example. If the sides of a square were quadrupled, the area would become sixteen times larger.
Doubling the length of the sides of a square results in the area being quadrupled (four times the original area).
Area = length*width new Area = 2 * length * width Area is doubled
i belive it is 60
135
2.5 cm. If the area of a pentagon is increased by 12.5 cm and each side of the pentagon is the same length, then each side would increase by 2.5 cm. (12.5 cm/ 5 sides = 2.5 cm/ side.
Doubling the length of the sides of a square results in the area being quadrupled (four times the original area).
No, it will be quadrupled.
If 6 is the side of a regular pentagon, the area is 61.937
Area = length*width new Area = 2 * length * width Area is doubled
Area = 172.05 cm2
the new area will be fourfold, not doubled. try it on squared paper and see how the shape increases from one square into four...
The Area of a square can be written as it's side length^2, orA = s^2if the side length is doubled, then s' is 2s.A' = (s')^2A' = (2s)^2A' = 4s^2 = 4*AWhen the side length is doubled, the area increases by a factor of 4
The area increases by a factor of 4.
A regular pentagon has five (5) equilateral triangles within it. Find the area of each triangle (1/2bh where b is the base of the triangle or the length of a side of the pentagon, and h is the height of the triangle or the apothem of the pentagon) and multiply the area of the triangle times five (5).
What is the area of a regular pentagon with side length of 9.4 feet and an apothem length of 6.5 feet
The surface area is quadrupled.
i belive it is 60