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Q: What will happen to the area of a pentagon if the side is doubled?

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Doubling the length of the sides of a square results in the area being quadrupled (four times the original area).

Area = length*width new Area = 2 * length * width Area is doubled

i belive it is 60

135

2.5 cm. If the area of a pentagon is increased by 12.5 cm and each side of the pentagon is the same length, then each side would increase by 2.5 cm. (12.5 cm/ 5 sides = 2.5 cm/ side.

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No, it will be quadrupled.

If 6 is the side of a regular pentagon, the area is 61.937

Doubling the length of the sides of a square results in the area being quadrupled (four times the original area).

Area = length*width new Area = 2 * length * width Area is doubled

Area = 172.05 cm2

the new area will be fourfold, not doubled. try it on squared paper and see how the shape increases from one square into four...

Double the force applied by that piston and half the speed that it moves.

The Area of a square can be written as it's side length^2, orA = s^2if the side length is doubled, then s' is 2s.A' = (s')^2A' = (2s)^2A' = 4s^2 = 4*AWhen the side length is doubled, the area increases by a factor of 4

The area increases by a factor of 4.

i belive it is 60

386.5

The surface area is quadrupled.

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