The area would become four times larger. The area increase is always the perimeter increase, squared. For example. If the sides of a square were quadrupled, the area would become sixteen times larger.
Doubling the length of the sides of a square results in the area being quadrupled (four times the original area).
Area = length*width new Area = 2 * length * width Area is doubled
i belive it is 60
135
2.5 cm. If the area of a pentagon is increased by 12.5 cm and each side of the pentagon is the same length, then each side would increase by 2.5 cm. (12.5 cm/ 5 sides = 2.5 cm/ side.
Doubling the length of the sides of a square results in the area being quadrupled (four times the original area).
No, it will be quadrupled.
If 6 is the side of a regular pentagon, the area is 61.937
Area = length*width new Area = 2 * length * width Area is doubled
Area = 172.05 cm2
the new area will be fourfold, not doubled. try it on squared paper and see how the shape increases from one square into four...
Double the force applied by that piston and half the speed that it moves.
The Area of a square can be written as it's side length^2, orA = s^2if the side length is doubled, then s' is 2s.A' = (s')^2A' = (2s)^2A' = 4s^2 = 4*AWhen the side length is doubled, the area increases by a factor of 4
The area increases by a factor of 4.
A regular pentagon has five (5) equilateral triangles within it. Find the area of each triangle (1/2bh where b is the base of the triangle or the length of a side of the pentagon, and h is the height of the triangle or the apothem of the pentagon) and multiply the area of the triangle times five (5).
What is the area of a regular pentagon with side length of 9.4 feet and an apothem length of 6.5 feet
The surface area is quadrupled.