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Alvera Stehr

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3y ago
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10y ago

It is written as cos6(t) - sin6(t) except that you use the symbol for theta instead of t. I have not tried inserting the theta symbol because this browser sometimes changes all characters to a Greek font.

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Q: Cos raised to power 6 theta - sin raised to power 6 theta?
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Prove that sin theta power 8 - cos theta power 8 equal to sin sq Theta -cos sq x 1-sin sq Theta cos sq theta?

The equation cannot be proved because of the scattered parts.


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'csc' = 1/sin'tan' = sin/cosSo it must follow that(cos) (csc) / (tan) = (cos) (1/sin)/(sin/cos) = (cos) (1/sin) (cos/sin) = (cos/sin)2


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(Sin theta + cos theta)^n= sin n theta + cos n theta


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The fourth Across the quadrants sin theta and cos theta vary: sin theta: + + - - cos theta: + - - + So for sin theta < 0, it's the third or fourth quadrant And for cos theta > 0 , it's the first or fourth quadrant. So for sin theta < 0 and cos theta > 0 it's the fourth quadrant


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You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.


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