The expression is not factorable with rational numbers.
3x+21x+9x=33x. Break it apart. The factor of x is x and the factors of 33 are 3 and 11. Therefore, the factors of 3x+21x+9x are 3, 11, and x.
The greatest common factor (GCF) is 7.
Make it equal zero by subtracting 21x from both sides. 20x2 - 21x - 5 factors to (4x - 5)(5x + 1)
3(7x-6)
3(7x + 11)
x
It is: 3x*(x+7)
To factor the expression 21x^35, you need to find the common factors of 21 and x^35. The factors of 21 are 1, 3, 7, and 21. The factors of x^35 are x, x^2, x^3, ..., x^35. Therefore, the factored form of 21x^35 is 21x*x^34 or 21x^(35-1).
(x - 8)(x - 13)
(2x - 1)(x - 10)
3x2-21x+36 =3(x2-7x+12) =3(x-4)(x-3)
(5x-6)(x-3)