figure out what x means and then multiply x by x then add the product of that and 2 and voila you get your answer
x3 - x2 + x - 2 has no rational factors.
x3 + 2x2 + 3x + 6 = x2(x + 2) + 3(x + 2) = (x + 2)(x2 + 3)
(x + 2)(x^2+4)
(x+1)(x+5)(x+2)
figure out what x means and then multiply x by x then add the product of that and 2 and voila you get your answer
x3 - x2 + x - 2 has no rational factors.
x3 - 2x2 + x - 2 =(x - 2)(x2 + 1)
x3 + 8 = x3 + 23 = (x + 2)[x2 - (x)(2) + 22] = (x + 2) (x2 - 2x + 4)
x3 + 2x2 + 3x + 6 = x2(x + 2) + 3(x + 2) = (x + 2)(x2 + 3)
x(x^2 + 2)
(x3+5x2+6x)/x to get x(x2+5x+6) find numbers that multiply to 6 and add to five (2 and 3) your factors are x, x+2, and x+3
(x + 2)(x^2+4)
(x+1)(x+5)(x+2)
x3 - 2x2 - 4x + 8 = (x2 - 4)(x - 2) = (x + 2)(x - 2)(x - 2)
(x + 5)(x^2 + 2x + 2)
(x + 2)(x^2 + 2x + 3)