0
0.3999999999999999
Denis Block
Wiki User
∙ 13y agoIntegrating x3 + 4x - 3.6 will give an expression for the area under the curve; then, given limits, the actual area can be calculated. So, to find the area under that curve bounded by x=a and x=b (and the x-axis, y=0), evaluate the definite integral:
a∫b x3 + 4x - 3.6 dx = [x4/4 + 2x2 - 3.6x]ab
= [(b4/4 + 2b2 - 3.6b) - (a4/4 + 2a2 - 3.6a)]
which would then be evaluated for the given values of a & b.
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Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc.
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