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PIEThe man is 5.96 feet tall and the lamp is 17.88 feet high.
18.6 m/52.6 degrees tan= 14.2
It depends on the time of day because the angle of the sun will determine the shadow length
A pole casting a shadow 49 feet long with an angle of elevation of the sun of 44.8 degrees is 50 feet tall. (47.98 rounded to two places)Tangent (theta) = opposite / adjacentTangent (44.9) = X / 49X = 47.98This does not take into account the curvature of the earth, but the error in this example is inconsequential, specifically an elevation error of about 0.015 percent.
That is an impossible question it could be any size the length of the shadow is dictated by the angle if the light source.
Your missing the angle of elevation or depression.
It is: 27.35 degrees rounded to two decimal places
36 degrees
tan(A) = 120/100 =39.81 degrees
Angle of elevation: tan-1(100/130) = 37.6 degrees rounded to one decimal place
The flagpole is 15.92 metres, approx.
Not enough information has been given to solve this problem such as: What is the angle of elevation?
tan-1(40/30) = 53.13° Therefore, the sun is at a 53.13° angle of elevation.
It is nearly 40 feet
If we assume the the flagpole makes a 90 degree angle with the ground, then the angle of elevator for the sun is 34.778°
Required angle has a tangent of 7.6/6.1 ie 1.249. This is 51.25 degrees.
You need more info, probably an angle of elevation or something like that. It may be 14ft tall.