4
No. they are parallel, since the slopes are both equal in this case 3. To be perpendicular the product of the slopes of both lines is equal to -1 (i.e., m1*m2 = -1).
To determine if the line ( y = 3x + 6 ) is perpendicular or parallel to another line, we need to compare their slopes. The slope of this line is 3. Two lines are parallel if they have the same slope, and they are perpendicular if the product of their slopes is -1. Therefore, without another line for comparison, we can't definitively state if it is perpendicular or parallel; we can only say that it has a slope of 3.
-1
y = 1/3x+4
No because the slope of the second equation is 1/4 and for it to be perpendicular to the first equation it should be 1/3
No. they are parallel, since the slopes are both equal in this case 3. To be perpendicular the product of the slopes of both lines is equal to -1 (i.e., m1*m2 = -1).
They are parallel because the slope has the same value in both equations.
To determine if the line ( y = 3x + 6 ) is perpendicular or parallel to another line, we need to compare their slopes. The slope of this line is 3. Two lines are parallel if they have the same slope, and they are perpendicular if the product of their slopes is -1. Therefore, without another line for comparison, we can't definitively state if it is perpendicular or parallel; we can only say that it has a slope of 3.
-1
As long as there are no exponents and your slope (ie 3) is a constant number, then it is parallel if the y-intercept is different.
y = 1/3x+4
We need to get both equations into slope-intercept form. If they are parallel, they will have the same slope. If they are perpendicular, they will have slopes that when multiplied equal -1. (unless one line is horizontal and the other vertical) 3x+2y=5 2y=5-3x y=(-3/2)x+(5/2) 3x+2y=9 2y=9-3x y=(-3/2)x+(9/2) The two lines are parallel, since both slopes are equal to (-3/2).
-3
3x+y = 4 y = -3x+4 Perpendicular slope: 1/3
y = 1/3x+4/3
No because the slope of the second equation is 1/4 and for it to be perpendicular to the first equation it should be 1/3
y = 3x + 1 y = 3x + 2 y = 3x + 3 y = 3x