Well first you will need another equation in order to establish whether it is perpendicular or parallel, But when plotting this line you get a positive vertical line.
No. they are parallel, since the slopes are both equal in this case 3. To be perpendicular the product of the slopes of both lines is equal to -1 (i.e., m1*m2 = -1).
-1
y = 1/3x+4
No because the slope of the second equation is 1/4 and for it to be perpendicular to the first equation it should be 1/3
y = 3x + 1 y = 3x + 2 y = 3x + 3 y = 3x
No. they are parallel, since the slopes are both equal in this case 3. To be perpendicular the product of the slopes of both lines is equal to -1 (i.e., m1*m2 = -1).
They are parallel because the slope has the same value in both equations.
-1
y = 1/3x+4
As long as there are no exponents and your slope (ie 3) is a constant number, then it is parallel if the y-intercept is different.
We need to get both equations into slope-intercept form. If they are parallel, they will have the same slope. If they are perpendicular, they will have slopes that when multiplied equal -1. (unless one line is horizontal and the other vertical) 3x+2y=5 2y=5-3x y=(-3/2)x+(5/2) 3x+2y=9 2y=9-3x y=(-3/2)x+(9/2) The two lines are parallel, since both slopes are equal to (-3/2).
-3
3x+y = 4 y = -3x+4 Perpendicular slope: 1/3
y = 1/3x+4/3
No because the slope of the second equation is 1/4 and for it to be perpendicular to the first equation it should be 1/3
y = 3x + 1 y = 3x + 2 y = 3x + 3 y = 3x
The parallel equation works out as: 4y = 3x+1 which can be expressed in the form of 3x-4y+1 = 0