No. they are parallel, since the slopes are both equal in this case 3. To be perpendicular the product of the slopes of both lines is equal to -1 (i.e., m1*m2 = -1).
-1
y = 1/3x+4
No because the slope of the second equation is 1/4 and for it to be perpendicular to the first equation it should be 1/3
y = 3x + 1 y = 3x + 2 y = 3x + 3 y = 3x
No. they are parallel, since the slopes are both equal in this case 3. To be perpendicular the product of the slopes of both lines is equal to -1 (i.e., m1*m2 = -1).
They are parallel because the slope has the same value in both equations.
-1
As long as there are no exponents and your slope (ie 3) is a constant number, then it is parallel if the y-intercept is different.
y = 1/3x+4
We need to get both equations into slope-intercept form. If they are parallel, they will have the same slope. If they are perpendicular, they will have slopes that when multiplied equal -1. (unless one line is horizontal and the other vertical) 3x+2y=5 2y=5-3x y=(-3/2)x+(5/2) 3x+2y=9 2y=9-3x y=(-3/2)x+(9/2) The two lines are parallel, since both slopes are equal to (-3/2).
-3
3x+y = 4 y = -3x+4 Perpendicular slope: 1/3
y = 1/3x+4/3
No because the slope of the second equation is 1/4 and for it to be perpendicular to the first equation it should be 1/3
y = 3x + 1 y = 3x + 2 y = 3x + 3 y = 3x
The parallel equation works out as: 4y = 3x+1 which can be expressed in the form of 3x-4y+1 = 0