I believe you can work that out. I'll get you started.
3,6,9,12 and just keep adding three until you get to 75.
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3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48,51,54,57,60,63,66,69,72,75
25, 50, 75
25,50,75
The first four multiples of five: 5, 10, 15, 20
The first 3 multiples of 13 are: 13, 26, and 39.
The total number of integers that are multiples of 25 and 6 is infinite. The first few are these: 150, 300, 450, 600, 750, 900 . . .
25, 50, 75, 100, 125, 150, 175.
The first six multiples of 3 are 3, 6, 9, 12, 15, and 18.
975
75, 150, 225.
Three multiples of 3 and 25 are: 75, 150, 225.
75, 150, 225
Sum of first 25 multiples of 44+8+12....100taking 4 common4(1+2+3+4....+25) = 4*325 =1300
12, 24, and 36
25 and 50
The sum of the first 25 numbers is 25*26/2 = 325 So the sum of the first 25 multiples of 12 is 325*12 = 3900
30, 60, 90, 120, 150
The first 50 multiples of 6 are the first fifty even multiples of 3.
Multiply it by the 1st ten odd numbers: 1*25 = 25, 3*25 = 75, 5*25 = 125 .... etc
The 3 first multiples of 75 are: 1, 3, and 5.