1st equation: x-y-z = 0
2nd equation: 2x-y+2z = 1
3rd equation: x-y+z = -2
Multiply all terms in 1st equation by 3 then add all equations together:-
So: 6x-5y = -1
Multiply all terms in 3rd equation by 2 and subtract it from the 2nd equation:-
So: y = 5
Therefore by means of substitution: x = 4, y = 5 and z = -1
They are simultaneous equations and their solutions are x = 41 and y = -58
The solutions are: x = 4, y = 2 and x = -4, y = -2
Simultaneous equations.
These are two expressions, not equations. Expressions do not have solutions, only equations do. NB equations include the equals sign.
Another straight line equation is needed such that both simultaneous equations will intersect at one point.
Through a process of elimination and substitution the solutions are s = 8 and x = 5
They are simultaneous equations and their solutions are x = 41 and y = -58
The solutions are: x = 4, y = 2 and x = -4, y = -2
Simultaneous equations.
If: 2x+y = 5 and x2-y2 = 3 Then the solutions work out as: (2, 1) and ( 14/3, -13/3)
These are two expressions, not equations. Expressions do not have solutions, only equations do. NB equations include the equals sign.
Another straight line equation is needed such that both simultaneous equations will intersect at one point.
1
The solutions work out as: x = 52/11, y = 101/11 and x = -2, y = -11
I notice that the ratio of the y-coefficient to the x-coefficient is the same in both equations. I think that's enough to tell me that their graphs are parallel. So they don't intersect, and viewed as a pair of simultaneous equations, they have no solution.
Without any equality signs the given expressions can't be considered to be simultaneous equations and so therefore no solutions are possible.
Just one.