Whenever there are a million or more items.
A 14-digit number is typically referred to as a "14-digit number." In mathematics, numbers are generally identified by the number of digits they contain, such as a 3-digit number, 7-digit number, etc. In computing, a 14-digit number may also be referred to as a "14-digit integer" or "14-digit numerical value."
There are 9 1-digit numbers and 16-2 digit numbers. So a 5 digit combination is obtained as:Five 1-digit numbers and no 2-digit numbers: 126 combinationsThree 1-digit numbers and one 2-digit number: 1344 combinationsOne 1-digit numbers and two 2-digit numbers: 1080 combinationsThat makes a total of 2550 combinations. This scheme does not differentiate between {13, 24, 5} and {1, 2, 3, 4, 5}. Adjusting for that would complicate the calculation considerably and reduce the number of combinations.
Assuming that the first digit of the 4 digit number cannot be 0, then there are 9 possible digits for the first of the four. Also assuming that each digit does not need to be unique, then the next three digits of the four can have 10 possible for each. That results in 9x10x10x10 = 9000 possible 4 digit numbers. If, however, you can not use the same number twice in completing the 4 digit number, and the first digit cannot be 0, then the result is 9x9x8x7 = 4536 possible 4 digit numbers. If the 4 digit number can start with 0, then there are 10,000 possible 4 digit numbers. If the 4 digit number can start with 0, and you cannot use any number twice, then the result is 10x9x8x7 = 5040 possilbe 4 digit numbers.
what is the greatest 4-digit number you can make with the digit 0,1,2,3, and 4
The number of six digit numbers that you can make from ten different digits ifrepetitions of same digit on the six digit number is allowed is 1 000 000 numbers(including number 000 000).If no repetitions of the the same digit are allowed then you have:10P6 = 10!/(10-6)! = 151 200 different six digit numbers(six digit permutations form 10 different digits).
If 11 and 111 is counted as 1 digit, the answer is 119.If 11 is counted as 2 digit 1's, the answer is 131.
There are 17 such numbers.
3 digit numbers are lessthan 4 digit numbers
A 3 or 4 digit number.
3897
Multiplying by multi-digit numbers is similar to multiplying by two-digit numbers in that both processes involve breaking down the numbers into place values and multiplying each digit by each digit in the other number. The key similarity lies in the application of the distributive property, where each digit in one number is multiplied by each digit in the other number, and then the products are added together to get the final result. This process is consistent whether you are multiplying by a two-digit number or a multi-digit number.
The ratio of the number of one-digit prime numbers to the number of one-digit composite numbers is one to one. The one-digit prime numbers are 2, 3, 5, and 7. The one-digit composite numbers are 4, 6, 8, and 9. Therefor, the ratio is 4:4, which simplifies to 1:1.
There are four of each.
A 400-digit number is typically referred to as a "400-digit number." In mathematics, numbers are categorized by their number of digits, such as single-digit numbers, double-digit numbers, triple-digit numbers, and so on. Therefore, a number with 400 digits would simply be called a "400-digit number."
Answer1 x 9 (number of 1 digit numbers) plus 2 x 89 (number of 2 digit numbers) plus 3(number of 3 digit numbers) x 347 = 1228 The correct answer is 1323. Here is how you do it.1 digit numbers = 92 digit numbers = 90 (99-9) number of 2 digit numbers - number of 1 digit numbers3 digit numbers = 378 (477-99) number of 3 digit numbers - number of 1 & 2 digit numbersSo, the solution is:1x9 = 92x90 = 1803x378 = 11349+180+378 = 1323
There are 900 3-digit numbers, 100 to 999. The 3 may be in the hundreds place, the tens place, or the ones. The numbers 300 - 399 have 3 in the hundreds place. The numbers 130, 131 ... 938, 939 have 3 in the tens place. The numbers 103, 113, 123 ... 993 have 3 in the ones place. That would total 100 + 90 + 90 = 280 except that now we have double counted some numbers with 2 or more threes in them. I believe if you count carefully you will find 19 double counted numbers in the 300 - 399 group and 8 numbers with the tens digit and ones digit equal to 3. Lastly, the number 333 was triple counted. 280 - 28 = 252. There are several ways to solve this problem. I encourage you to double-check my results ... who is to say this is correct?
There is no underlined digit. If there was it would be that digit multiplied by 10n-1 where n is the number of the digit as counted from the right hand end, starting at 1.