0
Want this question answered?
Be notified when an answer is posted
Add your answer:
Earn +20 pts
If SecASinA equals 0 then what will be the Value of CosA?
secA(sinA)=0 (1/cosA)(sinA)=0 tanA=0 Therefore A is in 1st or 3rd Quadrant i.e A=0 Degrees, 180 Degrees.... This yields cosA=1 or cosA=-1
How do you use a calculator for the law of sines say you have SinB.96 how to you get B?
well in order to get sine b you will have to got to your calculator and reverse the equation ... in other words on the calculator you will see sin-1 you will hit that and in the parenthesis you put .96 .so it should look like this sin-1(.96) and you qet your answer .!
How do you solve the equation h equals -16t2 plus 64t plus 1224 for h?
-16t2 + 64t + 1224 = 0 Multiply both sides by -1 16t2 - 64t - 1224 = 0 Divide both side by 8 2t2 - 8t - 153 = 0 Cannot be factored so use the formula (-b (+ or -)(root of b2 - 4ac)) / 2a
What is the answer to 35x to the second plus 34x plus 8 when factoring?
Presumably this is a quadratic equation question in the form of 35x2+34x+8 = 0 35x2+34x+8 = 0 (7x+4)(5x+2) = 0 Answer: x = -7/4 or x = -2/5 Usually you can factorise a quadratic equation by trial and improvement but in this case it's quicker to use the quadratic equation formula.
Why are there two sine cosine and tangent ratios?
There aren't. There are three: Sine, Cosine and Tangent, for any given right-angled triangle. They are related of course: for any given angle A, sinA/cosA = tanA; sinA + cosA =1. As you can prove for yourself, the first by a little algebraic manipulation of the basic ratios for a right-angled triangle, the second by looking up the values for any value such that 0 < A < 90. And those three little division sums are the basis for a huge field of mathematics extending far beyond simple triangles into such fields as harmonic analysis, vectors, electricity & electronics, etc.
If cosA plus cosB 12 and sinA plus sinB 14 then tan(A2 plus B2)?
1 by 2
Which equation correctly represents the law of sines?
SinA/a = SinB/b = SinC/c
How do you find the leg of a triangle with no right angles?
By using the Sine rule: a/sinA = b/sinB = c/sinC
State the Sine Law in words?
The formula is a/sinA=b/sinB=c/sinC. The idea behind the equation is that the larger an angle is the larger the side across from it will be and the smaller the angle the smaller the side across from it will be.
Altitude of right triangle with only one side known?
Law of sines or cosines SinA/a=SinB/b=SinC/c
How do you use the sine rule to find an angle?
The Sine Rule is SinA/a = SinB /b = SinC/c For any given triangle, where two sides and one angle are known, use the Sine Rule If the two sides are 'a' & 'b' , and Angle 'B' is known then, initially ignore the C/c compoentne. So it reduces to SinA/a = SinB/b To find SinA Then SinA = aSinB/b For example if Angle B = 30 degrees , 'a' = 3 & 'b' = 5 Then substituting SinA = 3Sin30/ 5 First find the Sine of 30 , which is 0.5 Hence SinA = 3*0.5/5 SinA = 1.5/5 SinA = 0.3 Hence A = Sin^(-1) 0.3 (or ArcSin(0.3)) = 17.457.... degrees. NB Select any two terms from 'A/a' B/b , or C/c'. Do NOT try to use all three in one calculation. NNB Sometimes the Sine Rule is written as a/SinA = b/SinB = c/SinC However, it works just the same. Hope that helps!!!!!
Can you derive dimensions of Right angle triangle from angles and one length?
yes, Assume a,b and c are the lengths of the triangle and and A, B and C are the angles opposite those lengths. Use the following formula: a/SinA = b/SinB = c/SinC
What is the length of side b to the nearest whole number if side a 24 and angle A 42 degrees and angle B 87 degrees?
If you draw a line perpendicular to side c and intersecting the vertex of angle C, you make two right triangles. Let's call the perpendicular segment side d. Now the sinB = d/a, so d = a sinB = 24 * sin87° ≈ 23.967. SinA = d/b, so b = d ÷ sinA = 23.967 ÷ sin42° ≈ 36.
Law of sines and cosines in mathematics?
Consider a triangle with vertices A, B and C. Call the edge opposite a given vertex by the same letter, but lower case. So side a is opposite vertex A etc. Law of Sines says: SinA/a= SinB/b=SinC/c If you prefer, you can split the equation into multiple separate ones: SinA/a=SinB/b Sin A/a=SinC/c etc. (there is one more part of the law of Sines which most books leave out. If R is the radius of a circumcircle around triangle ABC, then SinA/a= SinB/b=SinC/c =2R and in case you forgot a circumcirlce of a triangle is a unique circle that passes through each of the triangle 3 vertices.) The law of Cosines says: a2 +b2 -2abCosC=c2 or a2 +b2 -2abCosB=b2 or a2 +b2 -2abCosA=a2
How do you prove the sine rule?
Imagine a random triangle ABC. It will make it easier if you draw it with angle C at the top. The opposite side of angle A is labelled a, the opposite side of angle B is labelled b and the opposite side of angle C is labelled c. Draw the altitude (height) from angle C so that it is perpendicular (at 90 degrees) to side c. Looking at this triangle, find expressions for the sines of angles A and B: sinA = h/b sinB = h/a Rearrange these two equations in terms of h: h = bsinA h = asinB As h = h, these equations can be set equal to each other and simplified to find the sine rule: bsinA = asinB sinA/a = sinB/b If you expand on this way of working, you can also find that sinA/a = sinB/b = sinC/c. You have now proven the sine rule for all triangles!
What is the length of the side of a triangular fence if one side is 100 feet and the other side is 200 feet?
Use the sine rule to find the the length of third side. Sine rule: a/sinA = b/sinB = c/sinC
How can you know the last side of a triangle if you know the first two sides?
if it is a right triangle, use pythagorean theorem: a2+b2=c2 if not, and you have one of the angles, use law of sines: sinA/a=sinB/b=sinC/c
