I am assuming that the equation is 3*sin(t) = 1.5 even though the equality sign is not visible - due to the browser limitations.
Then sin(t) = 1.5/3 = 0.5
So t = sin-1(0.5) which gives the principal value of t = 0.5236.
The next value of t, in the domain, is pi - 0.5236 = 2.618 radians.
There are no further values in the specified domain.
sin(theta) = 15/17, cosec(theta) = 17/15 cos(theta) = -8/17, sec(theta) = -17/8 cotan(theta) = -8/15 theta = 2.0608 radians.
It means that 0 < theta < pi/2 radians or 90 degrees.
-Sin^(2)(Theta) + Cos^(2)Theta => Cos^(2)Theta - Sin^(2)Theta Factor (Cos(Theta) - Sin(Theta))( Cos(Theta) + Sin(Theta)) #Is the Pythagorean factors . Or -Sin^(2)Theta = -(1 - Cos^(2)Theta) = Cos(2)Theta - 1 Substitute Cos^(2)Thetqa - 1 + Cos^(2) Theta = 2Cos^(2)Theta - 1
You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.
-0.5736
Yes. (Theta in radians, and then approximately, not exactly.)
Pi radians is 180 degrees. So if you have theta in radians, multiply by 180/Pi
Theta is the measure of the angle, whether in degrees or radians.
r*theta = where theta is the angle measured in radians.= 5*120*pi/180 = 10.472 units (approx).r*theta = where theta is the angle measured in radians.= 5*120*pi/180 = 10.472 units (approx).r*theta = where theta is the angle measured in radians.= 5*120*pi/180 = 10.472 units (approx).r*theta = where theta is the angle measured in radians.= 5*120*pi/180 = 10.472 units (approx).
Yes. The derivation of the simple formula for the period of the pendulum requires the angle, theta (in radians) to be small so that sin(theta) and theta are approximately equal. There are more exact formulae, though.
[]=theta 1. sin[]=0.5sin[] Subtract 0.5sin[] from both sides.2. 0.5sin[]=0. Divide both sides by 0.5.3. Sin[] =0.[]=0 or pi (radians)
sin-1 (0.91) = about 1.14328 radians.
No, not necessarily. Cosine theta is equal to 1 only when theta is equal to zero and multiples of 2 pi radians or multiples of 360 degrees. This is because cosine theta is hypotenuse over adjacent, and the ratio 1 only occurs at 0, 360, 720, etc. or 0, 2 pi, 4 pi, etc.
To solve for the arc length when given only the central angle, you also need the radius of the circle. The formula for arc length ( L ) is given by ( L = r \theta ), where ( r ) is the radius and ( \theta ) is the central angle in radians. If the angle is provided in degrees, convert it to radians by using the formula ( \theta_{\text{radians}} = \theta_{\text{degrees}} \times \frac{\pi}{180} ). Once you have both the radius and the angle in radians, you can calculate the arc length.
Theta equals 0 or pi.
cos2(theta) = 1 so cos(theta) = ±1 cos(theta) = -1 => theta = pi cos(theta) = 1 => theta = 0
In a unit circle, the arc length ( s ) is directly equal to the angle ( \theta ) in radians. Therefore, if the arc length of a sector is 3 radians, the measure of the angle of the sector is also 3 radians.