Do you have a specific vertex fraction?
vertex = -b/2a
wuadratic = ax^ + bx + c
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y=2(x-3)+1
2
2 AND 9
You would convert it to vertex form by completing the square. You can also find the optimum value as optimum value and vertex are the same.
To find the vertex of a quadratic equation in standard form, (y = ax^2 + bx + c), you can use the vertex formula. The x-coordinate of the vertex is given by (x = -\frac{b}{2a}). Once you have the x-coordinate, substitute it back into the equation to find the corresponding y-coordinate. The vertex is then the point ((-\frac{b}{2a}, f(-\frac{b}{2a}))).