Assuming you have a rhombus SRQP, where PR and QS are the diagonals, you find the area by determining the area of the two triangles PQR and PRS, and adding them together.
The formula for finding the area of a triangle is (1/2)*base*height.
In our two triangles, the height is represented by 1/2 the length of SQ. In most math texts, this segment is referred to as y. PR (the other diagonal) is referred to as x.
For our purposes, the base of our triangles are both x. The height is one half of SQ, or y/2.
Area = (1/2)x * y/2 + (1/2)x * y/2
Simplify
Area = (xy/4) + (xy/4)
Combine those...
Area = 2xy/4
Simplify again
Area = (1/2)xy
Or
xy/2
QED
There is no relationship between the perimeter and the area of a rhombus. Take a rhombus with all 4 sides = 2 units. Therefore the perimeter is 8 units. There are an infinite number of possible areas for this rhombus. The largest possible area will be when the rhombus approaches the shape of a square = 4 square units. The smallest area will be when the one diagonal approaches 0 units and the other diagonal approaches 4 units (squashed almost flat). So two very extreme areas can have the same perimeter, including all those areas in-between.
You cannot. There is not enough information.
Perimeter = 4*Side so that Side = Perimeter/4 Area of a rhombus = Side * Altitude so Altitude = Area/Side = Area/(Perimeter/4) = 4*Area/Perimeter
The one alternative to find the area of a rectangle is when you are given the length of one diagonal and its slope.
Divide the rectangle in two triangles and then use the pythagorean theorem to find the remaining sides.
If side is given too, then you can find area with one diagonal. As diagonals bisect each other in a rhombus at 90°, Using Pythogoras Theorem: (Half d1)² = (side)² - (Half d2)²
Constructing the figure, we find the other diagonal to have length 10.The area of the rhombus would thus be 10x8x0.5=40
123
The answer is given below.
There is no relationship between the perimeter and the area of a rhombus. Take a rhombus with all 4 sides = 2 units. Therefore the perimeter is 8 units. There are an infinite number of possible areas for this rhombus. The largest possible area will be when the rhombus approaches the shape of a square = 4 square units. The smallest area will be when the one diagonal approaches 0 units and the other diagonal approaches 4 units (squashed almost flat). So two very extreme areas can have the same perimeter, including all those areas in-between.
That is one of the ways of finding the area of a rhombus. The area is half the product of the diagonals. In this case, 1/2 of 7 x 4.4 or .154. You can also find the area of a rhombus by using one side as the base and finding an altitude for that base and multiplying them. There is a third way using trigonometry.
You cannot. There is not enough information.
Given the length of the diagonal of the square ... call it 'D units'. The area of the square is (1/2 D2) (same units)2.
The length of the other diagonal works out as 12cm
The answer depends on what information you do have about the rhombus. Assuming that you know the length of the sides and one of the diagonals, then,In the triangle formed by the given diagonal and the sides of the rhombus, you know all three sides. So you can use the cosine rule to calculate the angle between the sides of the rhombus.The other pair of angles in the rhombus are its supplement.So now you know two sides and the included angle of the triangle formed by the missing diagonal and the sides of the rhombus.You can use the cosine rule again to find the missing diagonal.
If those are its diagonals then area is: 0.5*10*11 = 55 square units other wise use Pythagoras to find diagonal EG because area of a rhombus is 0.5 times the product of its diagonals.
Rhombus Area = side x height = 6 cm x 4 cm = 24 cm2In the right triangle formed by the side and the height of the rhombus, we have:sin (angle opposite to the height) = height/side = 4 cm/6cm = 2/3, so thatthe angle measure = sin-1 (2/3) ≈ 41.8⁰.In the triangle formed by two adjacent sides and the required diagonal, which is opposite to the angle of 41.8⁰ of the rhombus, we have: (use the Law of Cosines)diagonal length = √[62 + 62 -2(6)(6)cos 41.8⁰] ≈ 4.3Thus, the length of the other diagonal of the rhombus is about 4.3 cm long.