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Assuming you have a rhombus SRQP, where PR and QS are the diagonals, you find the area by determining the area of the two triangles PQR and PRS, and adding them together.

The formula for finding the area of a triangle is (1/2)*base*height.

In our two triangles, the height is represented by 1/2 the length of SQ. In most math texts, this segment is referred to as y. PR (the other diagonal) is referred to as x.

For our purposes, the base of our triangles are both x. The height is one half of SQ, or y/2.

Area = (1/2)x * y/2 + (1/2)x * y/2

Simplify

Area = (xy/4) + (xy/4)

Combine those...

Area = 2xy/4

Simplify again

Area = (1/2)xy

Or

xy/2

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Q: How do you find the area of a rhombus with only its diagonal given?
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How do I find the area of a rhombus with just one diagonal?

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