You mean 6 times 2 plus x plus 2? Well, do all the easy steps first, the is BEDMAS. If you don't know what it is. It's the order of doing operations:
Brackets then exponent then division AND multiplication then addition AND subtraction.
There is no brackets or exponents here, so we do 6 x 2 first
6 x 2 = 12 (We just have to accept to this cruel fact)
so it becomes
12 + x + 2
Addition is associative, at least over the integers, which is what these looks like. That is a + b = b + a for any a, b of choice. Or you can call it shuffle (signs carry, so 5 - 2 = -2 + 5 whatever -2 means)
so 12 + (+x) + (+2) = 12 + 2 + x, BEDMAS continues, we may do 12 + 2 = 14
so you get
14 + x.
What the heck is 14 + x? I don't know? You don't know? But who cares! This is pretty nice looking already. So it's simply 14 + x.
(x - 1)(x^2 - 5x + 2)
2x(3x+6) = 0 x = 0 or x = -2
6x2=-7
5x + 10 = 5(x+2) 6x2 + 12x = 6x(x+2) The only common factor is x+2
6(x - 2)(x - 1)
x3 6x2-x-30
x3 + 6x2 - 4x - 24 = (x + 6)(x2 - 4) = (x + 6)(x + 2)(x - 2)
6x2-18x+12 = (6x-6)(x-2)
2x(x + 5)(x - 2)
x5+4x4-6x2+nx+2 when divided by x+2 has a remainder of 6 Using the remainder theorem: n = 2
(3x - 5x) + (x2 - 6x2) = -2x -5x2 = -x(2 + 5x)
x3 - 6x2 + 4x + 15 = (x - 3)(x - (3/2 + √29/2))(x - (3/2 - √29/2)) ⇒ roots are x = 3, x = 3/2 + √29/2 (≈ 4.19), or x = 3/2 - √29/2 (≈ -1.19)