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How many different numbers can be represented by 3 bits?
1000
How many decimal numbers can be represented by 4-bits?
There are 16 decimal numbers that can be represented by 4-bits.
How many combinations can be formed from 6 bits?
26 = 64
How many combinations of bits are possible with two bits?
With two bits, there are (2^2) possible combinations, which equals 4. The combinations are: 00, 01, 10, and 11. Each bit can be either 0 or 1, leading to these four distinct configurations.
How many different number can be represented using 5 bits?
Using 5 bits, a total of (2^5) different numbers can be represented. This equals 32, allowing for values ranging from 0 to 31 in unsigned binary representation. If signed representation is used (e.g., two's complement), the range would be from -16 to 15, still totaling 32 distinct values.
How many bits are needed in order to represent the decimal values from 0 to 15?
4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.
How many different numbers can be represented by 3 bits?
1000
How many different binary codes can be represented in 2 bits?
2
How many different values can be represented by 12 bits?
2^12=4096
How many different data items can be represented by a group of n bits?
n2 -1
How many different symbols can be represented with 4 bits?
24 = 16
How many distinct combinations can be created with n bits?
The number of distinct combinations that can be created with n bits is 2n.
How many binary bits are necessary to represent 748 different numbers?
Binary bits are necessary to represent 748 different numbers in the sense that binary bits are represented in digital wave form. Binary bits also have an exponent of one.
How many decimal numbers can be represented by 4-bits?
There are 16 decimal numbers that can be represented by 4-bits.
How many different combinations are possible with 2 bytes?
1 byte is 8 bits. That's 8 1s or 0s. 2 bytes is 8*2=16 bits (1s/0s). That is 2^16=65536 possibilities. Therefore, there are 65,536 different combinations with 2 bytes.
How many combinations can be formed from 6 bits?
26 = 64
How many different values can be represented by 6 bits 7 bits 8 bits and 10 bits?
To find out how many different values can represented by a certain number of bits, we can use the following formula 2n-1 and that is because the first number is always a zero.Based on that 6 bits = 26- 1= 64-1=637 bits= 27-1= 1278 bits= 28-1=25510 bits= 210-1=1023# of bits1=12=33=74=155=316=637=1278=2559=51110=1023
