Slope 3 and point of (-1, 4)
Equation: y-4 = 3(x--1) => y = 3x+7
The equation of the line will also depend on its slope which has not been given and so an answer is not possible.
The straight line equation is: y = mx+c whereas m is the slope and c is the y intercept
y=3x-3
The equation is: y-2 = 2(x-4) => y = 2x-2
The equation is (y - 1) = 2(x - 1) or, y = 2x - 1
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
Slope: -3 Point: (4, -5) Equation: y = -3x+7
Point: (2, -1) Slope: -5 Equation: y = -5x+9
If you mean a point of: (2,1) then the equation works out as y = 3x-5
The equation of the line will also depend on its slope which has not been given and so an answer is not possible.
The straight line equation is: y = mx+c whereas m is the slope and c is the y intercept
y=2x+13
y=3x-3
The answe iss..... 6
y = 2x - 1
y=2x+1
It is: y = 2x-6