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What is the sum or difference of p and q?
The sum of p and q means (p+q). The difference of p and q means (p-q).
What is the proof of the modus ponens not by the truth table?
1)p->q 2)not p or q 3)p 4)not p and p or q 5)contrudiction or q 6)q
What is p lots of q?
p*q
What is converse inverse and contrapositive?
if the statement is : if p then q converse: if q then p inverse: if not p then not q contrapositive: if not q then not
What is p q and p q as a simultaneous equation?
p q and p q cannot be a useful part of a system of simultaneous equations since they are the same!
If p q and q r then p r. Converse statement B.A syllogism C.Contrapositive statement D.Inverse statement?
Converse: If p r then p q and q rContrapositive: If not p r then not (p q and q r) = If not p r then not p q or not q r Inverse: If not p q and q r then not p r = If not p q or not q r then not p r
What is the sum or difference of p and q?
The sum of p and q means (p+q). The difference of p and q means (p-q).
What is q²-p² divided by q-p?
q + p
What is the truth table for p arrow q?
Not sure I can do a table here but: P True, Q True then P -> Q True P True, Q False then P -> Q False P False, Q True then P -> Q True P False, Q False then P -> Q True It is the same as not(P) OR Q
If p is 50 of q then what percent of p is q?
If p = 50 of q then q is 2% of p.
How do you write the negation of if and then?
If p then q is represented as p -> q Negation of "if p then q" is represented as ~(p -> q)
Simplify pp - q - q q - p?
p-q
What does p over q mean in algebra?
P! / q!(p-q)!
Why does multiplication or division with a negative number yield a negative answer?
The assertion in the question is not always true. Multiplying (or dividing) 0 by a negative number does not yields 0, not a negative answer.Leaving that blunder aside, let p and q be positive numbers so that p*q is a positive number.Thenp*q + p*(-q) = p*[q + (-q)] = p*[q - q] = p*0 = 0that is p*q + p*(-q) = 0Thus p*(-q) is the additive opposite of p*q, and so, since p*q is positive, p*(-q) must be negative.A similar argument works for division.
How does every rational number have an additive inverse?
By definition, every rational number x can be expressed as a ratio p/q where p and q are integers and q is not zero. Consider -p/q. Then by the properties of integers, -p is an integer and is the additive inverse of p. Therefore p + (-p) = 0Then p/q + (-p/q) = [p + (-p)] /q = 0/q.Also, -p/q is a ratio of two integers, with q non-zero and so -p/q is also a rational number. That is, -p/q is the additive inverse of x, expressed as a ratio.
What type of operator can be used to determine whether a specific relationship that exists between two values?
The relational operators: ==, !=, =.p == q; // evaluates true if the value of p and q are equal, false otherwise.p != q; // evaluates true of the value of p and q are not equal, false otherwise.p < q; // evaluates true if the value of p is less than q, false otherwise.p q; // evaluates true if the value of p is greater than q, false otherwise.p >= q; // evaluates true of the value of p is greater than or equal to q, false otherwiseNote that all of these expressions can be expressed logically in terms of the less than operator alone:p == q is the same as NOT (p < q) AND NOT (q < p)p != q is the same as (p < q) OR (q < p)p < q is the same as p < q (obviously)p q is the same as (q < p)p >= q is the same as NOT (p < q)
Where p and q are statements p and q is called what of p and q?
The truth values.
