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Find an equation of the line containing the given point and having the given slope 3-6m1?
Assuming the point is (3, -6) and the slope 1, the equation is x - y - 9 = 0
What is the equation through point 0 negative 1 perpendicular to y equals 2x plus 5?
Given Point: (0,-1) Given Line: y=2x+5 If the line you are trying to find the equation of is perpendicular to the line given then the slope of the line you are trying to find must be the negative reciprocal of the line given. The slope of the line given is 2 so the slope of the line perpendicular to this one is -1/2. Using y=mx+b we get that y=(-1/2)x+b. Then we must use the point that was given to find b (the y-intercept). This means: -1=(-1/2)(0)+b -1=b So the equation is y=(-1/2)x-1
What is the point-slope form of a line with slope that contains the point (-2 1)?
The equation of the line will also depend on its slope which has not been given and so an answer is not possible.
What is the equation of a line that passes through the point 1 2 and is parallel to the x-axis?
Any equation parallel to the x-axis is of the form:y = constant In this case, you can figure out the constant from the given point.
Which is the equation of the line 3 1 and 0 0?
I assume that is a straight line between point (0, 0) and point (3, 1): The equation of any line is given by: y - yo = m(x - xo) where m is the gradient given by: m = (y1 - yo)/(x1 - x0) Thus, line is: y - 0 = (1 - 0)/(3 - 0)(x - 0) ⇒ y = 1/3 x or 3y = x
If the equation of a line has an undefined slope and passes through the point 1 3 which form would be used to write the equation of the line?
x = 1 (the line intersects the x-axis at 1, and is parallel to the y-axis)We cannot write the equation on the Slope-intercept form, since the slope of the line is undefined. 1 is the x-coordinate of any point on the given line.
Find an equation of the line containing the given point and having the given slope 3-6m1?
Assuming the point is (3, -6) and the slope 1, the equation is x - y - 9 = 0
What is the equation through point 0 negative 1 perpendicular to y equals 2x plus 5?
Given Point: (0,-1) Given Line: y=2x+5 If the line you are trying to find the equation of is perpendicular to the line given then the slope of the line you are trying to find must be the negative reciprocal of the line given. The slope of the line given is 2 so the slope of the line perpendicular to this one is -1/2. Using y=mx+b we get that y=(-1/2)x+b. Then we must use the point that was given to find b (the y-intercept). This means: -1=(-1/2)(0)+b -1=b So the equation is y=(-1/2)x-1
What is the point-slope form of a line with slope that contains the point (-2 1)?
The equation of the line will also depend on its slope which has not been given and so an answer is not possible.
How do I write the equation of the line that passes through the given point and is perpendicular to the given line Write the answer in slope-intercept form?
The standard equation for a straight line is y = mx + c. Let this be the equation of the original line. Note that m and c are known values. Let the given point coordinates be (a,b)Two straight lines are perpendicular if the product of their gradients (slopes) is -1.The slope (m1) of the perpendicular line is therefore m1 = -1/mWhen y = b then x = a so the equation for the perpendicular line is y = m1x + d, and substituting gives : b = -a/m + d and this will enable d to be calculated.NOTE : In the absence of information for the equation of the original line and the coordinates of the given point then this is a general rather than a specific answer.
Find an equation of the line having the given slope and containing the given point m equals 2 over 3 and 2 and -1?
If the slope is 2/3 and the coordinate is (2, -1) then the straight line equation is 3y=2x-7
What points are on the line given by the equation y equals 5x?
Any point on the line is a solution to the equation, and any solution to the equation is a point on the line. Ie any point where the y coordinate is 5 times the x coordinate will be on the line; for example the points (0, 0), (1, 5), (2, 10), (-1, -5), (-2, -10) all lines on the line y = 5x.
Find the equation of the line passing through the given point and perpendicular to the given line (5, 9); x-5y=8?
y = -(1/5)x + 9
Find equation perpendicular to given line contain given point?
If you know the slope of the line that your equation is perpendicular too, you find the negative reciprocal of it and use it as the slope for the line. (negative reciprocal = flip the slope over and change its sign. Ex: a slope of 2 has a negative reciprocal of -1/2. ) Then you use the given point, and put your equation in point-slope form. The general equation for point slope form is Y-y1=m(x-x1) The y1 is the y coordinate of the given point. X1 is the x coordinate of the given point. M is the slope that you found earlier. You now have your equation. If you are asked to put it in slope intercept form, simply distribute the numbers and solve the equation for y.
What is the point-slope form of a line with slope that contains the point (-1 2)?
Another point is needed to work out the slope and its straight line equation. Slope is worked out as: (y2-y1)/(x2-x1) ----------------------- With slope m and going through a point (x0, y0), a line has equation: y - y0 = m(x - x0) Thus the point-slope equation of a line with slope m through the point (-1, 2) is given by: y - 2 = m(x - -1) → y - 2 = m(x + 1)
The slope of the line below is 2 Write the point slope equation for the line using the coordinates of the labeled point 1 9?
The equation for a line of slope m going through point (Xo, Yo) is given by: y - Yo = m(x - Xo) So for line of slope 2 going through (1, 9) the equation is: y - 9 = 2(x - 1) ⇒ y = 2x + 7
What is the equation of a line that passes through the point 1 2 and is parallel to the x axis?
Any equation parallel to the x-axis is of the form:y = constant In this case, you can figure out the constant from the given point.
