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-- Call the three consecutive integers (x-1), x, and (x+1).

-- Twice the smallest is 2(x-1) or (2x-2).

-- 12 more than the largest is (x+1)+12 or (x+13).

-- These are equal, so

2x - 2 = x + 13

Subtract 'x' from each side of the equation:

x - 2 = 13

Add 2 to each side:

x = 15 .

-- The smallest of the three numbers is (x-1) = 14.

-- The three consecutive integers are 14, 15, and 16.

-- Twice the smallest is 28.

-- 28 is 12 more than 16.

QED, man, QED !

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Q: What are 3 consecutive integers such that twice the smallest is 12 more than the largest?

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5872345098234783904672083946728390752430689723409687298290843 theres your answer

They are (14, 15, 16).

three consecutives numbers: a = smallest a+2 a+4 14 less = -14 than twice the smallest = 2a so... a+a+2+a+4=-14+2a 3a+6=-14+2a 3a-2a=-14-6 a=-20 answer: smallest = -20 greatest = -16

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This equation works out to 2x = x + 11. This is because the three consecutive odd integers can be represented by x, x + 2, and x + 4. From the equation 2x - x = 11, so x = 11. Checking, 2 times 11 = 22 which is 7 more than 15. The three integers are 11, 13 and 15.

7, 8, 9 Let x be the smallest of the three integers; thus, the integers are x, x+1, x+2. From the problem, we get: 2x=(x+2)+5=x+7 2x-x=7 x=7

The answer would be 10 12 and 14... 14 x 3 = 42 and 2(10 + 12) = 44. So the product of the largest integer and three is two less than twice the sum of the lower integers.

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Suppose the middle integer is 2a. Then the smallest is 2a-2 and the biggest is 2a+2. 4 times the smallest is 8a-8 So largest subtracted from the smallest is (8a-8) - (2a+2) = 6a-10 So, 6a-10 = 2*2a = 4a so that 2a = 10 So the integers are 8, 10 and 12.

Suppose the smallest integer is A. The next two even numbers are A+2 and A+4. Using the information supplied we can form an equation: 2A - 14 = A + A+2 + A+4 Rearranging: 2A - 14 = 3A + 6 -20 = A So the three integers are -20, -18 and -16.

If the largest integer is subtracted from four times the smallest, the result is 4 more than twice the middle integer. Let the smallest integer be x, then the others are x + 2 and x+ 4. Therefore 4x - (x + 4) = 2 (x + 2 ) + 4 Expanding, we get 4x -x -4 = 2x + 4 + 4 Gathering terms: x = 12 Thus the three integers are 12, 14 and 16.

-10 and -11.

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