To find the x-intercept of the equation (2x + 3y = 30), set (y = 0): (2x = 30), giving (x = 15). For the y-intercept, set (x = 0): (3y = 30), resulting in (y = 10). Therefore, the x-intercept is (15) and the y-intercept is (10).
The intercepts of 2x + 3y - 6z = 30 are(15, 0, 0), (0, 10, 0) and (0, 0 , -5).
To find the intercepts of the equation (2x + 3y - 6z = 30), we set two variables to zero at a time. For the x-intercept, set (y = 0) and (z = 0): (2x = 30) gives (x = 15). For the y-intercept, set (x = 0) and (z = 0): (3y = 30) gives (y = 10). For the z-intercept, set (x = 0) and (y = 0): (-6z = 30) gives (z = -5). Thus, the intercepts are ( (15, 0, 0) ), ( (0, 10, 0) ), and ( (0, 0, -5) ).
30+12x = 6(5+2x)
2x + 30 = 4x + 10 Subtracting 2x from each side, 30 = 2x + 10 Subtracting 10 from both sides 20 = 2x Dividing both sides by 2 10 = x x = 10
-1
The intercepts of 2x + 3y - 6z = 30 are(15, 0, 0), (0, 10, 0) and (0, 0 , -5).
The intercepts of 2x + 3y - 6z = 30 are(15, 0, 0), (0, 10, 0) and (0, 0 , -5).
x: x = 15 y: y = 10 z: z = -5
(3,3)
30+12x = 6(5+2x)
2x + 30 = 4x + 10 Subtracting 2x from each side, 30 = 2x + 10 Subtracting 10 from both sides 20 = 2x Dividing both sides by 2 10 = x x = 10
2x + 30 = 4x + 22 Subtracting 2x from both sides, 30 = 2x + 22 Subtracting 22 from both sides, 8 = 2x Dividing both sides by 2, 4 = x x = 4
-1
2x + 6 - 6x = 30= 6 - 4x = 30= -4x = 24= 4x = -24= x = -6
Subtract 2x from each side: 30 = 10x - 50;Add 50 to each side: 80 = 10xDivide each side by 10: 8 = x
It can be simplified to: 2x+33
y-intercept would be 10 and x intercept would be -6