Q: What are the x and y intercepts of 2x plus 3y equals 30?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

The intercepts of 2x + 3y - 6z = 30 are(15, 0, 0), (0, 10, 0) and (0, 0 , -5).

30+12x = 6(5+2x)

2x + 30 = 4x + 10 Subtracting 2x from each side, 30 = 2x + 10 Subtracting 10 from both sides 20 = 2x Dividing both sides by 2 10 = x x = 10

-1

I am having difficulty understanding your question. 12 + 20 = 10 is obviously false (12 + 20 = 32).If 4x + 14 = 2x + 30, then x must equal 8.

Related questions

The intercepts of 2x + 3y - 6z = 30 are(15, 0, 0), (0, 10, 0) and (0, 0 , -5).

x: x = 15 y: y = 10 z: z = -5

The intercepts of 2x + 3y - 6z = 30 are(15, 0, 0), (0, 10, 0) and (0, 0 , -5).

(3,3)

30+12x = 6(5+2x)

2x + 30 = 4x + 22 Subtracting 2x from both sides, 30 = 2x + 22 Subtracting 22 from both sides, 8 = 2x Dividing both sides by 2, 4 = x x = 4

2x + 30 = 4x + 10 Subtracting 2x from each side, 30 = 2x + 10 Subtracting 10 from both sides 20 = 2x Dividing both sides by 2 10 = x x = 10

2x + 6 - 6x = 30= 6 - 4x = 30= -4x = 24= 4x = -24= x = -6

-1

y-intercept would be 10 and x intercept would be -6

Subtract 2x from each side: 30 = 10x - 50;Add 50 to each side: 80 = 10xDivide each side by 10: 8 = x

I am having difficulty understanding your question. 12 + 20 = 10 is obviously false (12 + 20 = 32).If 4x + 14 = 2x + 30, then x must equal 8.