They are -2, 2, 6, 10 and 14.
5
8
There are infinitely many possible rules that can be used to generate the 7 number sequence given in the question.One such is Un = (4n6 - 102n5 + 1015n4 - 4980n3 + 12511n2 - 14928n + 6720)/60 for n = 1 , 2, 3, ...There are infinitely many possible rules that can be used to generate the 7 number sequence given in the question.One such is Un = (4n6 - 102n5 + 1015n4 - 4980n3 + 12511n2 - 14928n + 6720)/60 for n = 1 , 2, 3, ...There are infinitely many possible rules that can be used to generate the 7 number sequence given in the question.One such is Un = (4n6 - 102n5 + 1015n4 - 4980n3 + 12511n2 - 14928n + 6720)/60 for n = 1 , 2, 3, ...There are infinitely many possible rules that can be used to generate the 7 number sequence given in the question.One such is Un = (4n6 - 102n5 + 1015n4 - 4980n3 + 12511n2 - 14928n + 6720)/60 for n = 1 , 2, 3, ...
5, 7, 9, 11 and 13
5/12 is in its lowest terms.
4n6 means forensics
+4n6!n4 +0 ..
5
it is 8.
The first five positive integer terms for 3n + 4 are: 1 = 7 2 = 10 3 = 13 4 = 16 5 = 19
2
5 first terms in n²+3
5
20, 15, 10, 5, 0, -5, -10, -15, -20 and so on.
To find the first 5 terms, plug 1, 2, 3, 4 and 5 in for n:3*1-3 = 03*2-3 = 33*3-3 = 63*4-3 = 93*5-3 = 12The first five terms are 0, 3, 6, 9 and 12.
5, 11, 17, 23, 29
4,8,12,16,20