They are -2, 2, 6, 10 and 14.
5
8
5, 7, 9, 11 and 13
There are infinitely many possible rules that can be used to generate the 7 number sequence given in the question.One such is Un = (4n6 - 102n5 + 1015n4 - 4980n3 + 12511n2 - 14928n + 6720)/60 for n = 1 , 2, 3, ...There are infinitely many possible rules that can be used to generate the 7 number sequence given in the question.One such is Un = (4n6 - 102n5 + 1015n4 - 4980n3 + 12511n2 - 14928n + 6720)/60 for n = 1 , 2, 3, ...There are infinitely many possible rules that can be used to generate the 7 number sequence given in the question.One such is Un = (4n6 - 102n5 + 1015n4 - 4980n3 + 12511n2 - 14928n + 6720)/60 for n = 1 , 2, 3, ...There are infinitely many possible rules that can be used to generate the 7 number sequence given in the question.One such is Un = (4n6 - 102n5 + 1015n4 - 4980n3 + 12511n2 - 14928n + 6720)/60 for n = 1 , 2, 3, ...
To simplify the expression (3c - 7 + 2c - 5), first combine like terms. The (c) terms (3c) and (2c) add up to (5c), while the constant terms (-7) and (-5) combine to (-12). Therefore, the simplified expression is (5c - 12).
"4n6" is a common abbreviation for "forensics," typically used in the context of digital forensics or forensic science. It represents the combination of the four letters in "forensics" (4) and the two letters in "n" and "6".
+4n6!n4 +0 ..
5
it is 8.
5 first terms in n²+3
2
5
20, 15, 10, 5, 0, -5, -10, -15, -20 and so on.
To find the first 5 terms, plug 1, 2, 3, 4 and 5 in for n:3*1-3 = 03*2-3 = 33*3-3 = 63*4-3 = 93*5-3 = 12The first five terms are 0, 3, 6, 9 and 12.
5, 11, 17, 23, 29
4,8,12,16,20
8