They are -10, -4, 2, 8, 14 and 20.
They are -2, 2, 6, 10 and 14.
Ignoring the "9" , then this is a Fibonacci sequence. 2,2,4,6,10 The first two terms are 'seed' terms then successive terms equal the sum of the two previous terms. 2 + 2 = 4 2 + 4 = 6 4 + 6 = 10 The next term would be 6 + 10 = 16.
8
To simplify the expression ( 7w + 6 - 10w - 2 ), combine like terms. First, combine the ( w ) terms: ( 7w - 10w = -3w ). Next, combine the constant terms: ( 6 - 2 = 4 ). The simplified expression is ( -3w + 4 ).
The sum of the first five terms of a geometric series can be calculated using the formula ( S_n = a_1 \frac{1 - r^n}{1 - r} ), where ( a_1 ) is the first term, ( r ) is the common ratio, and ( n ) is the number of terms. Here, ( a_1 = 6 ), ( r = 13 ), and ( n = 5 ). Substituting these values into the formula gives: [ S_5 = 6 \frac{1 - 13^5}{1 - 13} = 6 \frac{1 - 371293}{-12} = 6 \cdot \frac{-371292}{-12} = 6 \cdot 30939 = 185634 ] Thus, the sum of the first five terms is 185634.
They are -2, 2, 6, 10 and 14.
123456
-2,-4,-6.
Ignoring the "9" , then this is a Fibonacci sequence. 2,2,4,6,10 The first two terms are 'seed' terms then successive terms equal the sum of the two previous terms. 2 + 2 = 4 2 + 4 = 6 4 + 6 = 10 The next term would be 6 + 10 = 16.
8
In simple terms, it doesn't matter. x<6 is the same as 6>x.
They are: 6 15 24 33 and 42
If you mean nth term 2n then the 1st four terms are 2 4 6 and 8
To simplify the expression (6 + 2r + 3 + 8r), first combine like terms. The constant terms (6) and (3) add up to (9), while the variable terms (2r) and (8r) combine to (10r). Thus, the simplified expression is (9 + 10r).
The first three terms for the expression 2n-6 are obtained by substituting n with consecutive integers. When n=1, the expression evaluates to -4; when n=2, the expression evaluates to -2; and when n=3, the expression evaluates to 0. Therefore, the first three terms are -4, -2, and 0.
To find the sum of the first 48 terms of an arithmetic sequence, we can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum of the first n terms, a1 is the first term, and an is the nth term. In this case, a1 = 2, n = 48, and an = 2 + (48-1)*2 = 96. Plugging these values into the formula, we get: S48 = 48/2 * (2 + 96) = 24 * 98 = 2352. Therefore, the sum of the first 48 terms of the given arithmetic sequence is 2352.
It means you divide the first number of the problem by 7, then multiply that by 6. There is your answer.