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Q: What are the intercepts of 2x 3y-6z equals 30?

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The intercepts of 2x + 3y - 6z = 30 are(15, 0, 0), (0, 10, 0) and (0, 0 , -5).

The intercepts of 2x + 3y - 6z = 30 are(15, 0, 0), (0, 10, 0) and (0, 0 , -5).

12

12x - 5(2x - 6) = 30 12 x - 10x + 30 = 30 2x = 0, x = 0 y = -6

2x-17=13 2x=30 x=15

2x - 10 =30 2x -10 = 30 +10 +10 2x = 40 /2 /2 x = 20

Substitute 2x - 6 for y in first equation: 12x - 5(2x - 6) = 30 ie 12x - 10x + 30 = 30 so 2x = 0 making x = 0 and y = -6

x=6 y=30

2x-5=25 2x=25+5 x=30/2 x=15

x=6.

30+12x = 6(5+2x)

5x -6y=-30 5x-6y=30 (2x+3y) (2x-3y)=30 4x+6y=30 4x=30 x=30/4

2x + 30 = 4x + 22 Subtracting 2x from both sides, 30 = 2x + 22 Subtracting 22 from both sides, 8 = 2x Dividing both sides by 2, 4 = x x = 4

2x + 30 = 4x + 10 Subtracting 2x from each side, 30 = 2x + 10 Subtracting 10 from both sides 20 = 2x Dividing both sides by 2 10 = x x = 10

2x + 6 - 6x = 30= 6 - 4x = 30= -4x = 24= 4x = -24= x = -6

(3,3)

basically: simplify. -6 (5-2x)=54 (-30)-2x=-324 -30x=-162 x=-132

Subtract 2x from each side: 30 = 10x - 50;Add 50 to each side: 80 = 10xDivide each side by 10: 8 = x

-1

2x+y=-12-4x-2y=30 x=-y/2+30, you plug this into -12-4x-2y=30 and get -12+2y-120-2y=30 which gives 2y-2y=162. This is not possible, so the equation is unsolvable.

y-intercept would be 10 and x intercept would be -6

30-2x 6 x 5 = 30

write it as 2 separate equations: 12x-5y=30 2x-6=30 Now the easiest thing to do is solve the second equation: 2x=36 x=36/2 x=18 Now just plug x=18 into the first equation: 12*18-5y=30 216-5y=30 -5y=-186 y=37.2

2x - 3 = 57 or 3x + 15 = 105 or many others

10 - 3x = x - 2x + 40 10 - 3x = - x + 40 10 - 40 = 3x - x -30 = 2x -15 = x