A + B + C + 1 = 7 It equals seven because A=1 because it is the first letter in the alphabet, B=2 because it is the second letter in the alphabet, C=3 because it is the third letter in the alphabet, and 1=1 because it just does. So 1+2+3+1=7
b+b+b+c+c+c+c =3b+4c
b=2 a=1 c=3 so b plus a =c
2b + 2c or 2(b + c)
And how does this relate to coins?
A+c= 2a+b
b+b+b+c+c+c+c =3b+4c
b + b + b + c + c + c + c = 3b + 4c
b=2 a=1 c=3 so b plus a =c
a+b+c+d+e = 30 (i) c+e = 14 (ii) d+b = 1 (iii) a = 2b-1 (iv) a+c = 10 (v) By (i)-(ii)-(iii): a = 15 then, by (iv): b = 8 and by (v): c = -5 Also, b = 8 so by (iii): d = -7 and then by (i), e = 19
It is impossible to give any decimal/numeric value if we are not given the values of at least one variable, so the answer is B + B + B + C + C + C.
2b + 2c or 2(b + c)
And how does this relate to coins?
a= (+a) or a= (-) b= 2a b= 2a c= (-a) c= (+a)
A+c= 2a+b
If a + b + c + d + 80 + 90 = 100, then a + b + c + d = -70.
If: a = b+c+d Then: c = a-b-d
Because there is no way to define the divisors, the equations cannot be evaluated.