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What else can I help you with?
What is 3s plus 1?
3s + 1
How many 3s go into 140?
To find out how many 3s go into 140, divide 140 by 3. This gives you approximately 46.67. Since we're looking for whole 3s, you can fit 46 complete 3s into 140.
What is 12r-15s-r plus 3s?
12r - 15s - r + 3s = 11r -12s
How do you make four with four 3s?
4=4(3s) 4=12s s= 1/3
3s in 21?
7
What is 3s plus 1?
3s + 1
What is 135 equals 3s plus 15?
135=3s +15 120=3s 40=s
how many 3 are in 6037234789333333333333333333333333363?
28 3s
How many 3s go into 140?
To find out how many 3s go into 140, divide 140 by 3. This gives you approximately 46.67. Since we're looking for whole 3s, you can fit 46 complete 3s into 140.
How do you do -7 equals 3s-1?
-7 = 3s - 1 +1 +1 (add 1 to both sides to get the variable alone) ___ ____ -6 = 3s __ ___ (-6 and 3s both divided by 3) 3 3 -2 = s
What is 4 3s written as a rational number?
4 3s = 4*3 = 12, which is a rational number.
How do you solve an inequality with a negative coefficient?
The easiest way is to "flip" the inequality symbol end divide by the negative number:Example:6 < 3 - 3s6 - 3 < 3 - 3s -33 < -3s Method a) Divide by negative coefficient and flip the inequality symbol3/-3 > -3s/-3-1 > s or s< -13 < -3s Method b) Full algorithm, eliminate -3s by adding 3s on both sides3 +3s < -3s + 3s3 + 3s < 03 - 3 + 3s < 0 -33s < -33s/3 < -3/3s < -1 Looks familiar? So basically if you perform the full algorithm (method b) you can understand why we flip the inequality symbol when we have to eliminate a negative coefficient but it is faster just to flip the symbol (method a)
What is 12r-15s-r plus 3s?
12r - 15s - r + 3s = 11r -12s
Balance 2H2S plus SO2-H2o plus 3s?
2h2s + so2 - 2h20 + 3s
4R + 3s + 2r = 6r + 3s is what property?
The equation 4R + 3s + 2r = 6r + 3s is an example of the distributive property of addition, where the term 4R is being distributed over the sum of 2r and 6r. To see this more clearly, we can rewrite the equation as: 4R + 3s + 2r = (4R + 6r) + 3s Notice how the terms 4R and 6r are combined and the distributive property allows us to simplify the left-hand side of the equation.
How do you make four with four 3s?
4=4(3s) 4=12s s= 1/3
What is the least common multiple of the monomial a 3s and s2?
Well, honey, the least common multiple of a monomial like a^3s and s^2 is simply a^3s^2. You just gotta take the highest power of each variable that appears in either monomial, slap 'em together, and there you have it. Math made sassy.
