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What is x if the question is log4 7x5?
To solve for ( x ) in the equation ( \log_4 7x = 5 ), we can rewrite it in exponential form: ( 7x = 4^5 ). Calculating ( 4^5 ) gives us ( 1024 ), so we have ( 7x = 1024 ). Dividing both sides by 7 results in ( x = \frac{1024}{7} ), which simplifies to approximately ( 146.29 ).
What is the answer to log4 (3x 5)(x-6)3?
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "divided by", "equals", "squared", "cubed" etc. Please use "brackets" (or parentheses) because it is impossible to work out whether x plus y squared is x + y^2 of (x + y)^2.
A logarithm is an exponent?
A logarithm is quite the opposite of an exponential function. Whereas an exponential is y=ax , a log is logay=x For example, log39=2 because you raise 3 by the 2nd power to get 9. In other words, log39=2 because 32=9 Logarithms are present because they are a handy way to solve exponential equations, and because calculators use them to great advantage.
Log3 81 x log2 8 x log4 2 equals x?
log3 81 × log2 8 × log4 2 = log3 (33) × log2 (23) × log4 (40.5) = 3 × (log3 3) × 3 × (log2 2) × 0.5 × (log4 4) = 3 × 1 × 3 × 1 × 0.5 × 1 = 9 × 0.5 = 4.5
How do you express log4 7 as a single logarithm with base 2?
The rule for converting log bases is: log4(7) = log2(7)/log2(4) Now 4 = 2 squared so log2(4) = 2 So log4(7) = log4(7)/2 = (1/2)*log2(7) By the way, the "new and improved" browser now does not accept subscripts or superscripts so I hope you understand this.
What is the expression with the logarithm Log 4 plus Log 3?
log4+log3=log(4x3)=log12
The value of log log4log4x equals 1 then x equals?
the value of log (log4(log4x)))=1 then x=
Could you Condense the expression 5log4 2 plus 7 log4 x plus 4 log 4 y?
You use the identities: log(ab) = b log(a), and log(ab) = log a + log b. In this case, 5 log42 + 7 log4x + 4 log4y = log432 + log4x7 + log4y4 = log4 (32x7y4).
How do you solve k equals log4 91.8?
k=log4 91.8 4^k=91.8 -- b/c of log rules-- log 4^k=log 91.8 -- b/c of log rules-- k*log 4=log91.8 --> divide by log 4 k=log 91.8/log 4 k= 3.260
Log 4 64 equals y?
Log4 64=y 64=4y 26=22y Therefore y=3
What does log2x2 equal?
Since you did not provide a base for your logarithm there is no particular solution. In most cases it is best to assume it is to the base 10. So the answer would be: log(2*2)=log4 (to the base 10) log4=0.60205.... It is good practice to list the base to which the logarithm is at - normally written as a subscript in the lower right hand corner of the 'log'. The only exception is when the logarithm is to the base e, in which case we write it as ln(x) - where x is a real number. For more information check http://en.wikipedia.org/wiki/Logarithm
Can anyone solve for x log 4 X plus 16 plus log 4 X plus 4 equals 3?
log4(x) +16 +log4(x) +4=32log4(x)=-17log4(x)=-17/2x=4^(-17/2)=========================Since the parentheses have been lost from the question,it could easily be interpreted this way instead, (as well asa few others):x log(4x) + 16 + log(4x) + 4 = 3(x + 1) log(4x) = -174x = 10-17/(x+1)4x = the (x+1)th root of 10-17Come on back and solve that one for us.
What is x if the question is log4 7x5?
To solve for ( x ) in the equation ( \log_4 7x = 5 ), we can rewrite it in exponential form: ( 7x = 4^5 ). Calculating ( 4^5 ) gives us ( 1024 ), so we have ( 7x = 1024 ). Dividing both sides by 7 results in ( x = \frac{1024}{7} ), which simplifies to approximately ( 146.29 ).
What is the value of x that satisfies the equation 2 log 4 Bracket 7 x Bracket - 5 equals 0 Is - Please show working out?
2log4(7x) - 5 = 0 2log4(7x) = 5 log4(7x) = 5/2 7x = 45/2 =(41/2)5 = 25 = 32 x = 32/7
What is the answer to log4 (3x 5)(x-6)3?
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "divided by", "equals", "squared", "cubed" etc. Please use "brackets" (or parentheses) because it is impossible to work out whether x plus y squared is x + y^2 of (x + y)^2.
