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The rule for converting log bases is:

log4(7) = log2(7)/log2(4)

Now 4 = 2 squared so log2(4) = 2

So log4(7) = log4(7)/2 = (1/2)*log2(7)

By the way, the "new and improved" browser now does not accept subscripts or superscripts so I hope you understand this.

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โˆ™ 2014-07-04 17:28:45
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Q: How do you express log4 7 as a single logarithm with base 2?
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What does log2x2 equal?

Since you did not provide a base for your logarithm there is no particular solution. In most cases it is best to assume it is to the base 10. So the answer would be: log(2*2)=log4 (to the base 10) log4=0.60205.... It is good practice to list the base to which the logarithm is at - normally written as a subscript in the lower right hand corner of the 'log'. The only exception is when the logarithm is to the base e, in which case we write it as ln(x) - where x is a real number. For more information check

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Pretty much, yeah. It's just another way of expressing exponents. Say you know the following: (we'll start off easily) 16 = 42 You could also write that as: log4 16 = 2 Algebraically, a = bc so, logb a = c (b is known as the base, so it is read: log base b of a equals c) Also, logb a = (log a) / (log b)

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How do you solve the equation 5.2 log4 2x16?

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Can anyone solve for x log 4 X plus 16 plus log 4 X plus 4 equals 3?

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