4 5 6 7 8 9 10 11 12 13
It is 1062882.
Finding the nth term is much simpler than it seems. For example, say you had the sequence: 1,4,7,10,13,16 Sequence 1 First we find the difference between the numbers. 1 (3) 4 (3) 7 (3) 10 (3) 13 (3) 16 The difference is the same: 3. So the start of are formula will be 3n. If it was 3n, the sequence would be 3,6,9,12,15,18 Sequence 2 But this is not our sequence. Notice that each number on sequence 2 is 2 more than sequence 1. this means are final formula will be: 3n+1 Test it out, it works!
nth term is 8 - n. an = 8 - n, so the sequence is {7, 6, 5, 4, 3, 2,...} (this is a decreasing sequence since the successor term is smaller than the nth term). So, the sum of first six terms of the sequence is 27.
IT is A.P. Arithmetic progressionFormula to solven th term = First_term + ( n - 1)*difference_between_two_non=9first term=7difference_between_two_no = nth_term - (n-1)th_term = 5-7 = 3-5 =1-3 = -2nth term = 7+8*(-2) = -9Another Answer:-The nth term = 9-2n
3^n+2+3^n = 6^n+2 *'to the power of' can be represented with this symbol ^ .
1st term= 3 2nd term = 5 Nth term = 2n+1 10th term= 21 = 2(10)+1
3,6,9,12.....
The nth term of a sequence is the general formula for a sequence. The nth term of this particular sequence would be n+3. This is because each step in the sequence is plus 3 higher than the previous step.
2n+4/2 term 1 = 3 term 2 = 4 term 3 = 5 term 4 = 6
Strangely enough, it is 9n + 1 for n = 1, 2, 3, ...
Maybe 21 which is the 10th odd number OR 37 which is the 10th prime number
The general term for the sequence 0, 1, 1, 2, 2, 3, 3 is infinite sequence.
27
3
3
Each term in the sequence is three times the previous term plus two, so the next term is 485.1 (3 x 1 + 2) 5 (3 x 5 + 2) 17 (3 x 17 + 2) 53 (3 x 53 = 2) 161 (3 x 161 + 2) 485
The 19th term of the sequence is 16.