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It depends on what the 7' and 10' refers to. They could be adjacent sides of a rectangle or a parallelogram. If the latter, more information is required before the question can be answered.

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12y ago
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6mo ago

The diagonal of a rectangle with sides measuring 7 feet and 10 feet can be calculated using the Pythagorean theorem. The square of the diagonal is equal to the sum of the squares of the two sides, so in this case, the diagonal would be √(7^2 + 10^2) = √(49 + 100) = √149 = approximately 12.21 feet.

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Q: What is the diagonal of 7' and 10'?
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How long is the diagonal of a rectangle with dimensions 7in by 10in?

You use the pythagorous theorm to calculate the hypotenuse of the triangle, which is the same line as the diagonal. 7(7)+ 10(10)= diagonal x diagonal 149= diagonal x diagonal Diagonal= square root of 149: this approximates to 12.207in Visit quickanswerz.com for more math help/tutoring! Consider a rectangle with dimensions 7 inches by 10 inches. Let ABCD be the rectangle. We need to find the length of the diagonal. We know that the diagonals of a rectangle are same in length. So, it is enough to find the length of the diagonal BD. From the rectangle ABCD, it is clear that the triangle BCD is a right angled triangle. So, we can find the length of the diagonal using the Pythagorean Theorem. BD2 = BC2 + DC2 BD2 = 102 + 72 BD2 = 100 + 49 BD2 = 149 BD = √149 BD = 12.207 So, the length of the diagonal is 12.21 inches. Source: www.icoachmath.com


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