x = -2
Slope: 5 Points: (-2, -3) Equation: y = 5x+7
what is through (-3 , 2), slope -4 =
y=-2/3x-4/3
If you mean points of (-3, 2) and (5, -5) then the equation works out as 8y = -7x-5
THE QUESTION IS ACTUALLY WORDED. FIND THE EQUATION OF THE LINE THAT CONTAINS THE POINTS P1(-7,-4) AND P2(2,-8). ALGEBRA
Points: (4, -4) and (-2, 0) Slope: -2/3 Equation: y = -2/3x-4/3 or as 3y = -2x-4
Equation of the straight line: y = -3/5x+2 in slope intercept form
It has no equation as such because plotting the line on a grid will produce a vertical straight line parallel to the y axis.
y=2x+13
y = 2x + 1.
It is: y-5 = 2(x-1) => y = 2x+3
Equation of line: y - yo = m (x - xo) y - 6 = -2 (x - 3) y - 6 = -2x +6 y + 2x = 12