Each number is twice the previous number.
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∙ 2010-05-02 12:43:12the (n-1)th term plus the (n-2)th term.
The 19th term of the sequence is 16.
This is the Fibonacci sequence, where the number is the sum of the two preceding numbers. The nth term is the (n-1)th term added to (n-2)th term
Let n (i) = the term number of each term in the sequence., with (i) going from 1-6 E.g term number 1 (n (1) ) is 3. n(2)= -7 etc... Therefore n(i) for odd terms in the sequence is n (i)= (n (i -2)th term +1). For even terms in the sequence, n(i)= (n (i - 2)th term -3).
n2
The nth term of a arithmetic sequence is given by: a{n} = a{1} + (n - 1)d → a{5} = a{1} + (5 - 1) × 3 → a{5} = 4 + 4 × 3 = 16.
1. Each term is half the previous term.
1 - 2 - 4 - 8 - 16 - 32 - 64 the sequence doubles
The 8th term is 64. The sequence is the squares of the counting numbers. The nth term is given by t(n) = n².
1, 16, 81, 256 14641 is the 11th term.
the series can be 1,-4,16,-64
1, 4,9, 16, 25, 36,49 this is the next three sequence po