Each number is twice the previous number.
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∙ 14y agothe (n-1)th term plus the (n-2)th term.
This is the Fibonacci sequence, where the number is the sum of the two preceding numbers. The nth term is the (n-1)th term added to (n-2)th term
Let n (i) = the term number of each term in the sequence., with (i) going from 1-6 E.g term number 1 (n (1) ) is 3. n(2)= -7 etc... Therefore n(i) for odd terms in the sequence is n (i)= (n (i -2)th term +1). For even terms in the sequence, n(i)= (n (i - 2)th term -3).
The nth term of a arithmetic sequence is given by: a{n} = a{1} + (n - 1)d → a{5} = a{1} + (5 - 1) × 3 → a{5} = 4 + 4 × 3 = 16.
1 - 2 - 4 - 8 - 16 - 32 - 64 the sequence doubles
the (n-1)th term plus the (n-2)th term.
The 19th term of the sequence is 16.
This is the Fibonacci sequence, where the number is the sum of the two preceding numbers. The nth term is the (n-1)th term added to (n-2)th term
Let n (i) = the term number of each term in the sequence., with (i) going from 1-6 E.g term number 1 (n (1) ) is 3. n(2)= -7 etc... Therefore n(i) for odd terms in the sequence is n (i)= (n (i -2)th term +1). For even terms in the sequence, n(i)= (n (i - 2)th term -3).
The nth term of a arithmetic sequence is given by: a{n} = a{1} + (n - 1)d → a{5} = a{1} + (5 - 1) × 3 → a{5} = 4 + 4 × 3 = 16.
n2
1 - 2 - 4 - 8 - 16 - 32 - 64 the sequence doubles
1. Each term is half the previous term.
The 8th term is 64. The sequence is the squares of the counting numbers. The nth term is given by t(n) = n².
1, 16, 81, 256 14641 is the 11th term.
the series can be 1,-4,16,-64
1, 4,9, 16, 25, 36,49 this is the next three sequence po