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Q: What is the smallest number which must be added to 403 to make it divisible by 8?
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What is the smallest number whhich must be added to 75 to make a number exactly divisible by 9?

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403÷8 gives 50 as quotient and 3 as remainder. Dividend- remainder=divisor ×quotient 403-3=8*50 which is 400. our value is 403 So increase divisor 8*51=408. 403+5 gives 408. So 5 must be added to 403 to get a no divisible by 8.


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