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408 is the ans
Answer: 2A number is divisible by 3 if the sum of its digits is a multiple of 3.Now 2+1+4=7. If we add 2 more it is 9 which is a multiple of 3.So 216 is divisible by 3 since 2+1+6=9 which is a multiple of 3.
It is 8961 - W*int(8961/W)
20
101. This gets you to 1000 which is 10 cubed.
Seven
339 + 1 = 340,which is exactly divisible.
What number must be added to to make it equal to 190312
6. To check for divisibility by 9, add the digits of the number together and if the sum is divisible by 9, then the original number is divisible by 9. If the test is repeated on the sum(s) until a single digit remains, then this is the remainder when the original number is divided by 9. Subtracting this remainder from 9 will give the smallest number that needs to be added to to the original number to make it divisible by 9. For 75: 7 + 5 = 12 1 + 2 = 3 so 75 ÷ 9 has a remainder of 3, therefore add 9 - 3 = 6 to 75 to make it divisible by 9. (75 + 6 = 81 = 9 x 9).
6 (or 0)
403÷8 gives 50 as quotient and 3 as remainder. Dividend- remainder=divisor ×quotient 403-3=8*50 which is 400. our value is 403 So increase divisor 8*51=408. 403+5 gives 408. So 5 must be added to 403 to get a no divisible by 8.
408 is the ans
Answer: 2A number is divisible by 3 if the sum of its digits is a multiple of 3.Now 2+1+4=7. If we add 2 more it is 9 which is a multiple of 3.So 216 is divisible by 3 since 2+1+6=9 which is a multiple of 3.
the rule for divisibility by 9 is that the sum of all digits of the number should should be divisible by 9. So, 3+9+0+6+5= 23. To make is divisible by 9, we think of 27 (as the next number divisible by 9) and that means if we add 4 to any digit of the number, it will be divisible. 39069/9=4341
5621/12 =468 quotient ,5 remainder Next possibility increase quotient 469*12 gives 5628 now compare both their difference that is 5628-5621=7 so 7 must be added.
(560 ÷ 25) − 0.4 = 22 Therefore, the smallest number to subtract from 560 is 0.4 * 25 = 10
It is: 36 and so 960/48 = 20