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what is w if 2w = 16
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∙ 12y ago
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5w plus 2 equals 2w plus 5?
5w+2 = 2w+5 5w-2w = 5-2 3w = 3 w = 1
Solve for w 2l plus 2w equals P?
2l + 2w = P Subtract 2l from both sides: 2w = P - 2l Divide both sides by 2: w = P/2 - l
What is Length and width of a rectangular lot with a perimeter of 132 meters if the length is 8 meters more than the width?
2L+2W=132 L=W+8 substitute for L... 2(W+8)+2W=132 2W+16+2W=132 4W+16=132 2W+8=66 2W=58 W=29 L=W+8=29+8=37 So the width is 29 metres and the length is 37 metres
What is the width of a rectangle if length is 7 and perimeter is 42?
Let w be the width, then 2(7 + w) = 42 or 14 + 2w = 42 or 2w = 42 - 14 or 2w = 28 w = 14
What is 6 plus w-2w-11 plus 6w?
6 + w - 2w - 11 + 6w = -5 + 5w
What is the answer to 16 equals 4w plus 2w minus 2?
w = 3 16 = 4w + 2w - 2 Move the 2 to other side 16 + 2 = 4w + 2w 18 = 6w 18 / 6 = 3 = w
How do you solve 2w plus 16 equals -6w minus 8?
2w + 16 = - 6w - 8 2w + 16 + 6w = - 8 8w + 16 = - 8 8w = - 8 - 16 8w = - 24 w = - 3
What is the answer to this algebra 1 problem -36 plus 2w equals -8w plus w?
-36 + 2w = -8w + w -36 + 2w = -7w -36 = -7w - 2w -36 = -9w w = -36/-9 = 4
What plus what equals W?
W/3 + 2W/3 is one possible answer.
What is the answer for 14 equals 2w plus 6?
w=4
The perimeter of a rectangle is 32m and the area of the rectangle is 60 m2 Find the dimensions of the rectangle?
Perimeter, P = 32 mArea, A = 60 m^2.A = LW60= LWL = 60/WP = 2L + 2W32= 2L + 2W substitute 60/W for L;32= 2(60/W) + 2W divide by 2 to both sides;16 = 60/W + W multiply by W to both sides;16W = 60 + W^20 = 60 + W^2 - 16W or,W^2 - 16W + 60 = 0W = [16 +,- square root of [16^2 - (4)(1)(60)]/2W = [16 +,- square root of (256 -240)]/2W = (16 +,- square root of 16)/2W = (16 + 4)/2 or W = (16 - 4)/2W = 20/2 or W = 12/2W = 10 m or W = 6 mL = 60/W = 60/10 or L = 60/6L = 6 m or L = 10 m
If P equals 2L - 2W solve for L if P equals 40 and W equals 2?
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5w plus 2 equals 2w plus 5?
5w+2 = 2w+5 5w-2w = 5-2 3w = 3 w = 1
What is 5-32 plus 2w equals -7 equal to?
w=10
Solve for w 2l plus 2w equals P?
2l + 2w = P Subtract 2l from both sides: 2w = P - 2l Divide both sides by 2: w = P/2 - l
What is Length and width of a rectangular lot with a perimeter of 132 meters if the length is 8 meters more than the width?
2L+2W=132 L=W+8 substitute for L... 2(W+8)+2W=132 2W+16+2W=132 4W+16=132 2W+8=66 2W=58 W=29 L=W+8=29+8=37 So the width is 29 metres and the length is 37 metres
3w- plus 2 equals 2w plus 3?
3w - 2 = 2w + 3 Add 2 to both sides: 3w = 2w + 5 Subtract 2w from both sides: w = 5
