0
What else can I help you with?
What is x plus 4z-5-3x then x equals 2 and z equals 3x?
If the question is x + 4z - 5 - 3x when x = 2 and z = 3x, then First simplify the original statement x + 4z - 5 - 3x = 4z - 5 - 2x Secondly substitute in 3x for z 4z - 5 - 2x = 4*3x - 5 - 2x = 12x - 5 - 2x = 10x - 5 Lastly substitute 2 for the x 10x - 5 = 10*2 - 5 = 20 - 5 = 15 or x + 4z - 5 - 3x when x = 2 and z = 3x, so z = 3*2 = 6 x + 4z - 5 - 3x = 4z - 5 - 2x (replace the variables with the corresponding values) = 4*6 - 5 - 2*2 = 24 - 5 - 4 = 24 - 9 = 15
Use the Gauss-Jordan method to solve the equation 3x-5y-2z -9 -4x plus 3y plus z 11 8x-5y plus 4z 6?
Without an equality sign the given terms can't be considered to be an equation.
How do you factorise 9x-6y 12z?
What do 6, 9 and 12 have in common? 3. -6y / 3 = -2y +9x / 3 = +3x +12z / 3 = +4z Since they share 3, write 3 outside the brackets, and your solutions inside the brackets: 3(3x-2y+12z)
What is 9 to the 9 power?
It's 9*9*9*9*9*9*9*9*9 or 387,420,489
How do you get three different ways to get 10 only using the number 9?
9 + (9/9) = 10 (99/9) - (9/9) = 10 [ (9 + 9 + 9 + 9 + 9 + 9 + 9 + 9 + 9) / 9 ] + (9/9) = 10
What is 7 plus 4z equals 43?
7 + 4z = 437 + 4z -7 = 43 - 7 4z = 43 - 7 4z = 36 z = 9
If 4z-1 equals 9 what is z?
4z - 1 = 9 4z = 10 (add 1 to both sides) z = 2.5 (divide both sides by 4)
How do you factor Z2 -4Z - 45?
(z - 9)(z + 5)
What is x plus 4z-5-3x then x equals 2 and z equals 3x?
If the question is x + 4z - 5 - 3x when x = 2 and z = 3x, then First simplify the original statement x + 4z - 5 - 3x = 4z - 5 - 2x Secondly substitute in 3x for z 4z - 5 - 2x = 4*3x - 5 - 2x = 12x - 5 - 2x = 10x - 5 Lastly substitute 2 for the x 10x - 5 = 10*2 - 5 = 20 - 5 = 15 or x + 4z - 5 - 3x when x = 2 and z = 3x, so z = 3*2 = 6 x + 4z - 5 - 3x = 4z - 5 - 2x (replace the variables with the corresponding values) = 4*6 - 5 - 2*2 = 24 - 5 - 4 = 24 - 9 = 15
What is the solution to 7x plus y plus z equals 6 7x plus y plus 4z equals 9 y plus x equals 6?
7x + y + z = 6 7x + y + 4z = 9 y + x = 6 Take the first two statements and subtract them. 7x + y + z = 6 7x + y + 4z = 9 _____________ 0 + 0 - 3z = -3 Therefore: z = 1 Then you are left with: 7x + y + 1 = 6 7x + y + 4 = 9 which is impossible, so this is an impossible equation.
Solve the system of equations 3x - y 4z 9 2x 3y - 2z 16 4x - 3y z 1?
post an equation first.
How do you identify linear functions?
The powers (exponents) of each variable in the equation is 1. For example 5x + 6y = 9 is a line in 2-dimensional space, 2x + 3y +4z = 7 is a line in 3-d space, etc.
Use the Gauss-Jordan method to solve the equation 3x-5y-2z -9 -4x plus 3y plus z 11 8x-5y plus 4z 6?
Without an equality sign the given terms can't be considered to be an equation.
How do you factorise 9x-6y 12z?
What do 6, 9 and 12 have in common? 3. -6y / 3 = -2y +9x / 3 = +3x +12z / 3 = +4z Since they share 3, write 3 outside the brackets, and your solutions inside the brackets: 3(3x-2y+12z)
How do you factorise 9x 6y 12z?
What do 6, 9 and 12 have in common? 3. -6y / 3 = -2y +9x / 3 = +3x +12z / 3 = +4z Since they share 3, write 3 outside the brackets, and your solutions inside the brackets: 3(3x-2y+12z)
How do you solve 9-4z2?
You cannot solve this statment as there is nothing to equate to it. However, it will factor. 9 - 4z^2 First we note that both '9' and '4' are squared numbers. 9 = 3^(2) & 4 = 2^(2) So we can re-write the statement as 3^(2) - (2z)^(2) Note that it now has two squared terms with a negative between them . This will factor to 3^(2) = (2z)^2 = ( 3 - 2z_)(3 + 2z) NOTE the different signs. NB Two squared terms with a positive(+) between them will NOT factor.
How to solve the system of equations 4x plus 3y plus 2z equals 34 and 2x plus 4y plus 3z equals 45 and 3x plus 2y plus 4z equals 47?
4x + 3y + 2z = 34; 2x + 4y + 3z = 45; 3x + 2y + 4z = 47 First, eliminate terms in z from 2 of the equations, by muliplying first equation by 2 and subtracting third equation from the answer: 8x + 6y + 4z = 68, subtract leaving 5x + 4y = 21 (equation 4) Similarly multiply the first equation by 3 and the second by 2 giving 12x + 9y + 6z = 102 and 4x + 8y + 6z = 90 Subtract again and we have 8x + y = 12 or y = 12 - 8x Substitute this in equation 4 gives 5x + 4(12 -8x) = 21 Simplify: 5x + 48 - 32x = 21 = -27x = -27 so x = 1 y = 12 - 8x so y = 4 and in one of the original equations 4 + 12 + 2z = 34, ie 2z = 34 -16 so z =9 Check: 2x + 4y + 3z = 2 +16 + 27 = 45 and 3x + 2y + 4z = 3 + 8 + 36 = 47 QED!
