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60 square units.
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What is the area of rhombus ABCD if AC 7 and BD 12?
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals: Area = (1/2) * ( 12 * 7) = 42.
What is the area of rhombus ABCD if AC equals 12 and BD equals 7?
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals:Area = (1/2) * ( 12 * 7) = 42.The way this works: for a rhombus, the diagonals bisect each other (they intersect at the other's midpoint), so split this into two identical triangles BCD and BAD.The area of one of these triangles is (1/2) * Base * Height, with Base = length of BD, and Height = 1/2 length of AC.So area of one triangle = (1/2) * BD * ((1/2)*AC), and area of rhombus is 2 * area of triangle, so you have 2 * (1/2) * BD * ((1/2)*AC) = (1/2) * (BD) * (AC)
What is the area of a rhombus whose diagonals are 10 and 12 inches?
If you have a rhombus that has been divided into four in this way, each part has an equal area. Each part is also a right-angled triangle, whose perpendicular sides are of lengths 5 and 6 inches (since these will be half the distances of the diagonals of the rhombus). Draw a sketch and you will see that this is the case. The area of a right-angled triangle is given by: A = base x height / 2 = 5 inches x 6 inches / 2 = 15 square inches Since there are four of these triangles, each having an area of 15 square inches, the total area of the rhombus is given by: A = 4 x 15 square inches = 60 square inches
What is the area of rhombus DEFG if DF equals 12 and EG equals 9?
54 square units. BY:ANTONIO WOODSON
What is the perimeter of a rhombus whose area is 30 square cm and whose largest diagonal is 12 cm showing work?
Let the other diagonal be x If: 0.5*12*x = 30 then x = 60/12 => x = 5 The rhombus has four interior right angle triangles with lengths of 6 cm and 2.5 cm Using Pythagoras each equal sides of the rhombus works out as 6.5 cm Perimeter: 4*6.5 = 26 cm
What is the area of a rhombus with a diagonals of 10 feet and 12 feet?
Area of a rhombus= 1/2 (d₁) (d₂); where, d₁ and d₂ are the diagonals. Solution: A=1/2 (10) (12) = 60 feet²
What is the area of a rhombus with diagonals of 10 feet and 12 feet?
60 feet
What is the area of rhombus ABCD if AC 7 and BD 12?
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals: Area = (1/2) * ( 12 * 7) = 42.
What is the value of rhombus if it is 3x 12?
If you are wanting the area of a rhombus that have diagonals which lengths are 3 and 12, then the area is 18 square units.
What is the area of a rhombus whose diagonals measure 10m and 12m?
It is: 0.5*10*12 = 60 square m
Find the area of a rhombus with diagonals of 9 cm and 12 cm?
54
What is the rhombus of a with diagonals of 10 ft and 12 ft?
It is a rhombus with sides of length sqrt(61) feet = approx 7.8 feet.
What is the area of a rhombus with diagonals of 12 and 5?
The diagonals bisect each other. Since that is true then the area of the rhombus is the sum of the two triangles. Half of one diagonal times the other diagonal.2(6x5)/2 or 6x5=30
If the diagonals of the rhombus are in the ratio 3 to 4 and the perimeter of the rhombus is 40 cm what are the lengths of the diagonals?
The lengths of the diagonals work out as 12 cm and 16 cm
What is the area of a rhombus with the diagonals of 12 and 5?
area_rhombus = product_of_diagonals / 2 = 12 x 5 / 2 = 30 units2 [replace "units" by your measurement unit, eg cm]
What is the length of the sides of a rhombus whose diagonals are 10 and 12 respectively?
The diagonals of a rhombus intersect at 90 degrees therefore it has 4 right angle triangles with sides of 5 and 6 respectively with the hypotenuse being a side of the rhombus. So using Pythagoras' theorem: 52+62 = 61 and the square root of this is the length of each side of the rhombus which is approximately 7.81 units of measurement
What is the area of rhombus ABCD if AC equals 12 and BD equals 7?
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals:Area = (1/2) * ( 12 * 7) = 42.The way this works: for a rhombus, the diagonals bisect each other (they intersect at the other's midpoint), so split this into two identical triangles BCD and BAD.The area of one of these triangles is (1/2) * Base * Height, with Base = length of BD, and Height = 1/2 length of AC.So area of one triangle = (1/2) * BD * ((1/2)*AC), and area of rhombus is 2 * area of triangle, so you have 2 * (1/2) * BD * ((1/2)*AC) = (1/2) * (BD) * (AC)
