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Let the smallest consecutive odd integer be x, so the second will be x + 2, and the third one be x + 4. So we have:

x + (x + 2) = 8(x + 4)

2x + 2 = 8x + 32

2x - 8x + 2 - 2 = 8x - 8x + 32 - 2

-6x = 30

-6x/-6 = 30/-6

x = -5 (the first odd integer)

x + 2 = -5 + 2 = -3 (the second)

x + 4 = -5 + 4 = -1 (the third)

Thus, the three consecutive odd integers are -5, -3, and -1.

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