Let the smallest consecutive odd integer be x, so the second will be x + 2, and the third one be x + 4. So we have:
x + (x + 2) = 8(x + 4)
2x + 2 = 8x + 32
2x - 8x + 2 - 2 = 8x - 8x + 32 - 2
-6x = 30
-6x/-6 = 30/-6
x = -5 (the first odd integer)
x + 2 = -5 + 2 = -3 (the second)
x + 4 = -5 + 4 = -1 (the third)
Thus, the three consecutive odd integers are -5, -3, and -1.
Check:
Divide the sum of the three consecutive integers by 3: 138/3 = 46. The smallest of these integers will be one less than 46 and the largest will be one more than 46, so the three consecutive integers will be 45, 46, and 47.
Let's represent the three consecutive odd integers as ( 2n-1 ), ( 2n+1 ), and ( 2n+3 ), where ( n ) is an integer. According to the given information, twice the smallest integer ( 2(2n-1) ) is equal to seven more than the largest integer ( 2n+3 ). Setting up the equation, we have ( 4n-2 = 2n+3+7 ). Solving this equation gives us ( n = 6 ). Therefore, the three consecutive odd integers are 11, 13, and 15.
Divide the sum of the three consecutive odd integers by 3: 402/3 = 134. The smallest of these integers will be two less than 134 and the largest will be two more than 134, so the three consecutive odd integers will be 132, 134, and 136.
Divide the sum of the three consecutive odd integers by 3: 225/3 = 75. The smallest of these integers will be two less than 75 and the largest will be two more than 75, so the three consecutive odd integers will be 73, 75, and 77.
Divide the sum of the three consecutive odd integers by 3: 51 / 3 = 17. The smallest of these integers will be two less than 17 and the largest will be two more than 17, so the three consecutive odd integers will be 15, 17, and 19.
For x, which is the largest integer of nconsecutive positive integers of which the smallest is m:x = m + n - 1
Let the smallest integer be 2n, the next integer is 2n + 2, and the largest one is 2n + 4. Then, we have:2n + (2n + 2) = (2n + 4) + 164n + 2 = 2n + 202n = 18 the smallest integer2n + 2 = 18 + 2 = 20 the next one2n + 4 = 18 + 4 = 22 the largest integerCheck
The largest integer is 103 because 101+102+103 = 306
-1
9,11,13
Suppose the middle integer is 2a. Then the smallest is 2a-2 and the biggest is 2a+2. 4 times the smallest is 8a-8 So largest subtracted from the smallest is (8a-8) - (2a+2) = 6a-10 So, 6a-10 = 2*2a = 4a so that 2a = 10 So the integers are 8, 10 and 12.
5872345098234783904672083946728390752430689723409687298290843 theres your answer
Divide the sum of the three consecutive odd integers by 3: -147 /3 = -49. The smallest of these integers will be two less than -49 and the largest will be two more than -49, so the three consecutive odd integers will be -47, -49, and -51.
Given the sum of three consecutive integers 135, we write out the expression as:x + (x + 1) + (x + 2) = 135 where:x = smallest integerx + 1 = middle integerx + 2 = largest integerSolve for x by rearranging the terms:3x + 3 = 1353x = 132x = 44Therefore, the largest integer is x + 2 = 46.
If the largest integer is subtracted from four times the smallest, the result is 4 more than twice the middle integer. Let the smallest integer be x, then the others are x + 2 and x+ 4. Therefore 4x - (x + 4) = 2 (x + 2 ) + 4 Expanding, we get 4x -x -4 = 2x + 4 + 4 Gathering terms: x = 12 Thus the three integers are 12, 14 and 16.
You've come to the right place. The integers are: 2, 4, and 6
They are (14, 15, 16).