0
Remember 8 = 2^(3) & 27x^(3) = (3x)^3
Hence
2^(3) - (3x)^3 is of the form
x^(3) - y^(3) = ( x - y)(x^2 + xy + y^2)
Hence
2^(3) - (3x)^(3) = ( 2 - 3y)(2^(2) + (2)(3y) + (3y)^(2)) =>
2^(3) - (3y)^(3) = (2 - 3y)(4 + 6y + 9y^(2)) -
Done!!!!!
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Earn +20 ptsQ: How do you factor 8 minus 27x cubed?
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What is the factored form of 27x cubed minus eight?
27X^3-8 = 0 27X^3 = 8 X^3 = 8/27 X = cubic root of 8/cubic root of 27 = 2/3
How do you factor the expression x cubed minus 8?
(x3 - 8) is factored thus: (x - 2)(x2 + 2x + 4) The easiest way to do this is to remember the formula: (a3 - b3) = (a - b)(a2 + ab + b2)
How do you factor 9x squared minus 64?
(3x + 8)(3x - 8)
What is the factor 8 x cubed plus 125?
(2x + 5)(4x^2 - 10x + 25)
What is the cube of the number 8?
512 2 it's the cubed root of 8. 2x2=4 and 4x2=8 so 2 cubed equals 8. If it is 8 cubed then you have to take 8x8=64 and 64x8=512
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