Study guides

☆☆

Q: How do you factor 8 minus 27x cubed?

Write your answer...

Submit

Still have questions?

Continue Learning about Algebra

27X^3-8 = 0 27X^3 = 8 X^3 = 8/27 X = cubic root of 8/cubic root of 27 = 2/3

(x3 - 8) is factored thus: (x - 2)(x2 + 2x + 4) The easiest way to do this is to remember the formula: (a3 - b3) = (a - b)(a2 + ab + b2)

(3x + 8)(3x - 8)

8 cubed is equal to 512.

(2x + 5)(4x^2 - 10x + 25)

Related questions

27X^3-8 = 0 27X^3 = 8 X^3 = 8/27 X = cubic root of 8/cubic root of 27 = 2/3

27x - 8 is in its simplest form.

the answer is (3x-2)(9x squared+6x+4)

20x2 - 27x -8 20 * -8 is -160, and -32 and 5 add to -27 20x2 - 32x + 5x - 8 4x(5x-8) + 1(5x-8) (4x + 1)(5x-8)

I also need to know the answer to this problem. Can anyone answer it?

8(y - 1)(y^2 + y + 1)

8(y - 1)(y^2 + y + 1)

All that is factorable here is the common factor t.t3 - 8tt(t2 - 8)======

9 minus 8

000000

(x + 1)(x - 8)

0.2963

People also asked