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Remember 8 = 2^(3) & 27x^(3) = (3x)^3
Hence
2^(3) - (3x)^3 is of the form
x^(3) - y^(3) = ( x - y)(x^2 + xy + y^2)
Hence
2^(3) - (3x)^(3) = ( 2 - 3y)(2^(2) + (2)(3y) + (3y)^(2)) =>
2^(3) - (3y)^(3) = (2 - 3y)(4 + 6y + 9y^(2)) -
Done!!!!!
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What is the factored form of 27x cubed minus eight?
27X^3-8 = 0 27X^3 = 8 X^3 = 8/27 X = cubic root of 8/cubic root of 27 = 2/3
How do you factor the expression x cubed minus 8?
(x3 - 8) is factored thus: (x - 2)(x2 + 2x + 4) The easiest way to do this is to remember the formula: (a3 - b3) = (a - b)(a2 + ab + b2)
How do you factor 9x squared minus 64?
(3x + 8)(3x - 8)
What is the factor 8 x cubed plus 125?
(2x + 5)(4x^2 - 10x + 25)
How would the expression x cubed minus 8 be rewritten using the difference of cubes?
Answer: (x - 2)(x² + 2x + 4)Factor the difference of cubes:a³ - b³ = (a - b)(a² + ab + b² )note 8 = 2³ = 8 ⇒ b = 2 , with a = xSox³ - 8= x³ - 2³= (x - 2)(x² + 2x + 2²) = (x - 2)(x² + 2x + 4)
What is the factored form of 27x cubed minus eight?
27X^3-8 = 0 27X^3 = 8 X^3 = 8/27 X = cubic root of 8/cubic root of 27 = 2/3
How do you factor the expression 27x cubed plus 8?
the answer is (3x-2)(9x squared+6x+4)
How do you factor 20x squared minus 27x minus 8?
20x2 - 27x -8 20 * -8 is -160, and -32 and 5 add to -27 20x2 - 32x + 5x - 8 4x(5x-8) + 1(5x-8) (4x + 1)(5x-8)
Factor 24x cubed plus 27x squared - 8 x - 9?
I also need to know the answer to this problem. Can anyone answer it?
How do you Factor 8 minus cubed?
8(y - 1)(y^2 + y + 1)
How do you factor 8y cubed minus 8?
8(y - 1)(y^2 + y + 1)
How do you factor t cubed minus 8t?
All that is factorable here is the common factor t.t3 - 8tt(t2 - 8)======
What is 2 cubed minus 3 squared?
9 minus 8
4 cubed minus 8 squared?
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What is 8 divided by the square root of 27x?
0.2963
How do you factor squared minus 7x minus 8?
(x + 1)(x - 8)
X cubed minus 8 equals zero but the answer is 2 comma negative 1 plus and minus square root 3. How did they get this as the Answer?
x 3-8
