0
How do you find the distance from the origin to a point on the graph?
Wiki User
∙ 9y ago
-- square the point's x-coordinate
-- square the point's y-coordinate
-- add the two squares together
-- take the square-root of the sum
-- the answer is the distance of the point from the origin.
This works because if you draw a line down from the point to the x-axis (length is y-coordinate), then along the x-axis to the origin (length is x-coordinate), and back to the point (length is distance), you just made a right triangle.
Then you can use the Pythagorean Theorem to find the length of the long side (the distance) since you know the length of the two shorter sides.
Wiki User
∙ 9y ago
Add your answer:
Earn +20 pts
How do you locate rate of change on a graph?
Find the slope of the tangent to the graph at the point of interest.
Find the coordinates of a second point on the graph of a function f if the given point is on the graph and the function is even?
If the point (x,y) is on the graph of the even function y = f(x) then so is (-x,y)
How does one find out if an equation's graph goes through the origin?
-- Take the equation -- Set either 'x' or 'y' equal to zero -- Solve the resulting equation for the remaining variable -- If the remaining variable is then also zero, then the origin is on the graph of the function If the graph is a straight line ('x' and 'y' appear in the equation only to the 1st power), then the equation has to be in the form of a simple ratio ... like (y = Kx) or (x = Ky) or (xy = K) or (x/y = K) ... in order to go through the origin.
Which point does not lie on the graph of the equation 2x plus y equals 3?
It looks like this came from some multiple choice question, where you're given several choices. Take each choice and substitute the x and y coordinates into the equation. So for example the point is (0,3), then substitute in and get 2*0 + 3 which equals 3 and satisfies the equation, so the point is on the graph. If the point is (1,1) then 2*1 + 1 = 3 which satisfies the equation, so that point is also on the line. You want to find one where the left side does not equal 3, then that point is not on the graph of the line.
Find the intercepts for the graph of the equation given x plus 5y equals 0?
x + 5y = 0Subtract 5y from each side of the equation, just to put 'x' and 'y' on opposite sides.x = -5yThis is interesting. If EITHER 'x' OR 'y' is zero, then the other one is also zero.The only place on the graph where that is true is the origin. So the line goes through the origin,and the 'x' and 'y' intercepts are both zero.
Distance from origin to point?
The origin on a graph is the point (0,0).You can find the distance to a point by applying the Pythagorean theorem:Square the x coordinate and add it to the square of the y - coordinate of the point.Now take the square root of your answer.The result is the straight line distance from the origin to the point.
How do you find the distance from a point to a line?
graph it
To find the standard equation for a circle centered at the origin you used the distance formula since the radius measures?
The distance from any point on the circle to the origin
How can you find the unit rate on a graph that goes through the origin?
It is the gradient of the straight line joining the origin to any point on the graph. Thus, if A = (p,q) is any point on the graph, the average unit rate between the origin and A is q/p (provided p is non-zero).
To find the standard equation for a circle centered at the origin we use the distance formula since the radius measures?
A: The distance from any point inside the circle to the origin. B: The distance from any point inside the circle to the origin. C: The distance from the x-coordinate to the origin. D: The circumference.
How can you obtain the average velocity and instantaneous velocity from a displacement time graph?
To obtain the average velocity from a displacement-time graph, you can calculate the slope of the line connecting two points on the graph. Divide the change in displacement by the change in time. To obtain the instantaneous velocity, you need to find the slope of the tangent line at a specific point on the graph. Choose a point on the graph and draw a line tangent to the curve at that point. The slope of this tangent line will give you the instantaneous velocity at that specific point.
How to calculate distance from a velocity time graph?
You cannot since the graph shows displacement in the radial direction against time. Information on transverse displacement, and therefore transverse velocity, is not shown. For example, there is no difference in the graph of you're staying still and that of your running around in a circle whose centre is the origin of the graph. In both cases, your displacement from the origin does not change and so the graph is a horizontal line. In the first case the velocity is 0 and in the second it is a constantly changing vector. All that you can find is the component of the velocity in the radial direction and this is the slope of the graph at the point in question.
How can you find the unit rate on a gragh that goes through the origin?
Divide the ordinate (y-coord) of any point on the graph by its abscissa (x-coord).
How do you find the distance between two points on a graph?
The Law of Cosines: c^2=a^2 + b^2 -2abcos(ab) , c is the distance between the two points a and b and (ab) is the angle between a and b from the origin. If one point is taken as the origin, and a and b a re taken at right angles to each other, then cos(ab) is zero and you have Pythagora' Theorem..
How do you find the distance between the origin of a cartesian coordinate system and a point?
To find the distance between the origin and the point (x,y) use Pythagoras on the right angled triangle which has the points (0, 0), (x, 0), (x, y) - the distance is the hypotenuse of the triangle and so has length: distance = √(x2 + y2) This can be extended to find the distance between any two points (x1, y1) and (x2, y2): distance = √((x2 - x1)2 + (y2 - y1)2) (for the original question (x1, y1) is the origin (0, 0) and the first formula results.)
How do you plot a distance time graph when you are given a velocity time graph?
The area under a v/t graph is how far you've gone. Choose a point on the time axis, read off the speed and find the area underneath. If its a straight line graph, all you have to do is find the area of the triangle. This area is the distance travelled in this particular time. Repeat for several more points on the time axis. Plot distance against time.
How do you find the y intercept of a scatter plot?
Measure the distance between the point where the line intercepts the Y axis and the origin
