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If tan(theta) = x

then sin(theta) = x/(sqrt(x2 + 1) so that csc(theta) = [(sqrt(x2 + 1)]/x

= sqrt(1 + 1/x2)

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โˆ™ 2012-06-26 16:37:44
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A polynomial of degree zero is a constant term

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Q: How do you get the csc theta given tan theta in quadrant 1?
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