With all due respect, you don't really want to know howto solve it.
You just want the solution.
csc(Θ) = 1/sin(Θ)
tan(Θ) = sin(Θ)/cos(Θ)
csc(Θ) x tan(Θ) = 1/sin(Θ) x sin(Θ)/cos(Θ) = 1/cos(Θ) = sec(Θ)
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If tan(theta) = x then sin(theta) = x/(sqrt(x2 + 1) so that csc(theta) = [(sqrt(x2 + 1)]/x = sqrt(1 + 1/x2)
Remember that tan = sin/cos. So your expression is sin/cos times cos. That's sin(theta).
-2(cot2theta)
They are theta = -34.99 degrees and 145.09 deg.
Let 'theta' = A [as 'A' is easier to type] sec A - 1/(sec A) = 1/(cos A) - cos A = (1 - cos^2 A)/(cos A) = (sin^2 A)/(cos A) = (tan A)*(sin A) Then you can swap back the 'A' with theta